Question

用户必须将标题和数字输入两个EditText。一旦他点击提交，他在EditText中写的内容将被转换为String。现在面临的问题是，如何将这些字符串发布到RESTful Web服务

这是我的代码

submit.setOnClickListener(new View.OnClickListener(){

        @Override
        public void onClick(View v) {
            String tit = null;
            String number = null;

            HttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost("http://localhost:3000/api");

            if(title.getText()!=null){
                tit = title.getText().toString();
            }
            if(num.getText()!=null){
                number = num.getText().toString();
            }
        }
    });

请任何人都可以指导我或指导我如何做。

Answer 1

submit.setOnClickListener(new View.OnClickListener(){

  @Override
    public void onClick(View v) {
       String tit = null;
       String number = null;

       HttpClient httpClient = new DefaultHttpClient();
       HttpPost httpPost = new HttpPost("http://localhost:3000/api");

       if(title.getText()!=null){
          tit = title.getText().toString();
       }
       if(num.getText()!=null){
          number = num.getText().toString();
       }

       List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
       nameValuePairs.add(new BasicNameValuePair("title", tit));
       nameValuePairs.add(new BasicNameValuePair("number", number));
       httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
       HttpResponse response = httpclient.execute(httpPost);

    }
});

Answer 2

@Assad永远不会在UI线程上制作网络内容。

submit.setOnClickListener(new View.OnClickListener() {

            @Override
            public void onClick(View v) {
                String tit = title.getText().toString();
                String number = num.getText().toString();

                new PostDataTask().execute(new String[] { tit, number });

            }
        });

在AsyncTask或其他工作线程

下发出Http请求

class PostDataTask extends AsyncTask<String, Void, Boolean> {

        @Override
        protected Boolean doInBackground(String... params) {

            HttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost("http://localhost:3000/api");

            try {
                List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
                nameValuePairs.add(new BasicNameValuePair("title", params[0]));
                nameValuePairs.add(new BasicNameValuePair("number", params[1]));
                httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
                // HttpResponse response = httpClient.execute(httpPost);

                ResponseHandler<String> responseHandler = new BasicResponseHandler();

                String response = httpClient.execute(httpPost, responseHandler);
                return true;
            } catch (HttpResponseException e) {
                e.printStackTrace();
            } catch (UnsupportedEncodingException e) {
                e.printStackTrace();
            } catch (ClientProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return false;
        }

        @Override
        protected void onPostExecute(Boolean result) {
            super.onPostExecute(result);
            if (result) {
                // success
            } else {
                // failure
            }

        }

    }

将Android应用程序连接到RESTful Web服务

2 个答案: