Question

我希望在父级暂停时让子节点消失。

var plats: SKNode = SKNode();
var bigBox: SKSpriteNode!;

override func didMoveToView(view: SKView) {

    // Set anchor point
    self.anchorPoint = CGPointMake(0.5, 0.5);

    bigBox = SKSpriteNode(color: UIColor.redColor(), size: CGSizeMake(100, 100));
    bigBox.zPosition = 1;

    plats.addChild(bigBox);

    var smallBox: SKSpriteNode = SKSpriteNode(color: UIColor.greenColor(), size: CGSizeMake(50, 50));
    smallBox.zPosition = 2;
    bigBox.addChild(smallBox);

    self.addChild(plats);
}

//检测到触摸时暂停平板并尝试对孩子进行操作

override func touchesBegan(touches: Set<NSObject>, withEvent event: UIEvent) {

    // Here I pause the parent
    plats.paused = true;

    // Get the child node
    let smallBox: SKSpriteNode = bigBox.children[0] as! SKSpriteNode;

    println(smallBox);
    smallBox.paused = false;
    println(smallBox.paused); // return false but the action is never trigger

    // This part is never run, if I set plats.paused = false it will work but I dont that
    let scaleUp = SKAction.scaleTo(0.4, duration: 0.1);
    smallBox.runAction(scaleUp, completion: {
        self.bigBox.removeAllActions();
        self.bigBox.removeFromParent();
        println("done");
    });

}

多数民众赞成就是所有代码，你可以粘贴并试着看看它是否有效

xcode ver ：6.3 swift ver ：1.2

Answer 1

暂停节点后，节点及其所有后代将暂停。换句话说，您无法暂停父节点，并且其中一个子节点继续运行。

当父级暂停时，是否可以对子级执行操作

1 个答案: