Question

我认为标题有点模糊。我将在下面解释。所以我有这些表

约会表

id  created_by  created_by_id
---------------------------
1   provider        10
2   customer        5
3   admin           1

提供者表

id first_name last_name
------------------------
..    ...       ...
10     x         y

客户表

id  first_name  last_name
-------------------------
..     ...       ...
5       a         b

管理员表

id  first_name  last_name
--------------------------
..    ...          ...
1      c            d

我想根据created_by字段查询并返回相关帐户的全名，因此如果是提供者，则查询提供者表中的名称，依此类推。

我试过这个

select  *,
        (
            SELECT 
                CASE 
                    WHEN appointments.created_by='provider' THEN 
                        CONCAT(d.first_name, " ", d.last_name)
                    WHEN appointments.created_by='customer' THEN 
                        CONCAT(p.first_name, " ", p.last_name)
                    ELSE CONCAT(p.first_name, " ", p.last_name)
                END
            FROM providers as d, customers as p
            WHERE 
                appointments.created_by_id = (CASE 
                    WHEN appointments.created_by='provider' THEN 
                        d.id
                    WHEN appointments.created_by='customer' THEN 
                        p.id
                    ELSE p.id
                END)
        )
from appointments

但它似乎不起作用。你能帮我一个像这样的表吗？

id  created_by  name
-------------------
1    provider   x y
2    customer   a b
3     admin     c d

Answer 1

select *,
    case appointments.created_by 
        when 'admin' then (select concat(first_name, ' ', last_name)  from admins where admins.id = appointments.created_by_id)
        when 'customer' then (select concat(first_name, ' ', last_name)  from customers where customers.id=appointments.created_by_id)
        when 'provider' then (select concat(first_name, ' ', last_name)  from providers where providers.id = appointments.created_by_id)
    END as name
from appointments

这是一个带有案例方法的sqlfiddle：http://sqlfiddle.com/#!9/43510/1

MySQL根据表的字段从不同的表中查询

1 个答案: