我目前正在尝试取消与数据模型中的对象关联的特定UILocalNotifications。为此,每个数据对象都有一个唯一的标识符,即NSUUID
。
创建UILocalNotification:
/* Set UILocalNotification */
UILocalNotification *localNotification = [[UILocalNotification alloc] init];
localNotification.fireDate = date;
localNotification.alertBody = self.mytextfield.text;
localNotification.soundName = UILocalNotificationDefaultSoundName;
localNotification.applicationIconBadgeNumber = 1;
NSLog(@"making a notification: %@",[r.uniqueId UUIDString]);
[localNotification.userInfo setValue:[r.uniqueId UUIDString] forKey:@"uid"];
[[UIApplication sharedApplication] scheduleLocalNotification:localNotification];
然而,当我去删除通知并打印出每个通知内容时,通知的alertbody
被正确打印,但唯一标识符以某种方式丢失。这个实现有什么问题?
取消UILocalNotification:
Obj *r = (Obj *)[self.objects[indexPath.section] objectAtIndex:indexPath.row];
/* Cancel UILocalNotification */
NSArray *scheduleReminders = [[UIApplication sharedApplication] scheduledLocalNotifications];
NSLog(@"scheduled.count: %i",(int)scheduleReminders.count); // Correctly prints 3
for (int i = 0; i < scheduleReminders.count; i++)
{
UILocalNotification *notification = scheduleReminders[i];
NSDictionary *userInfoCurrent = notification.userInfo;
NSLog(@"searching through reminders: %i %@ %@ %@",(int)i,[userInfoCurrent objectForKey:@"uid"], notification.alertBody); // Alert body prints correctly
if ([[userInfoCurrent valueForKey:@"uid"] isEqualToString:[r.uniqueId UUIDString]])
{
NSLog(@"found it");
//Cancelling local notification
[[UIApplication sharedApplication] cancelLocalNotification:notification];
break;
}
}
答案 0 :(得分:3)
问题是userInfo是&#34; nil&#34;默认情况下。您应该分配自己的NSDictionary,设置uid,然后将此字典设置为localNotification.userInfo。