将标签替换为BeautifulSoup中的另一个标签

时间:2015-04-17 15:21:34

标签: python xml beautifulsoup

我正在尝试在XML文档中查找标记,并将其完全替换为新标记。我有我认为应该在下面工作的东西:

para = monograph.find('para', text='Some text.')
newpara = '<para>Some <emph type="bold">new</emph> text.</para>'
newpara = BeautifulSoup(newpara, 'xml')
para.replaceWith(newpara)

不幸的是,当我运行这个时,我得到了:

Traceback (most recent call last):
File "<input>", line 1, in <module>
File "C:\Python34\lib\site-packages\bs4\element.py", line 211, in replace_with
my_index = self.parent.index(self)
AttributeError: 'NoneType' object has no attribute 'index'

有什么建议吗?

1 个答案:

答案 0 :(得分:1)

您可以使用replaceWith()来实现此目标,这是一种方法:

In [8]: from bs4 import BeautifulSoup

In [9]: tree = BeautifulSoup('<html><body><div>Foo</div><div>Bar</div><para>Some text.</para></body></html>', 'xml')

In [10]: newpara = '<para>Some <emph type="bold">new</emph> text.</para>'

In [11]: newpara = BeautifulSoup(newpara, 'xml')

# here I use newpara.para as a shortcut to get the <para> element
# as a new BeautifulSoup will include wrapping tags
In [12]: tree.find('para', text='Some text.').replaceWith(newpara.para)
Out[12]: <para>Some text.</para>

In [13]: print tree
<?xml version="1.0" encoding="utf-8"?>
<html><body><div>Foo</div><div>Bar</div><para>Some <emph type="bold">new</emph> text.</para></body></html>

希望这有帮助。