Question

我想创建一个查询，在两个日期的手上对结果进行排序。这是一个switch语句。但这似乎不起作用。

简化版本下方（未指定字段）

SELECT *
FROM `system_booking` 
JOIN `system_address`       ON `system_address`.`address_id` = `system_booking`.`booking_address`
JOIN `system_bookingprice`  ON `system_booking`.`booking_id` = `system_bookingprice`.`bookingprice_link`
JOIN `system_vehicle`       ON `system_vehicle`.`vehicle_id` = `system_booking`.`booking_vehicle`
JOIN `system_parkingfee`    ON `system_booking`.`booking_id` = `system_parkingfee`.`parkingfee_link`
WHERE  (`booking_start` LIKE ? OR `booking_end` LIKE ?) 
ORDER BY (
   CASE WHEN `booking_start`  LIKE ?  THEN `booking_start`    ASC
   CASE WHEN `booking_end`    LIKE ?  THEN `booking_end`      ASC
END)

然而，这会产生MySQL错误。

您的SQL语法有错误;检查与您的MySQL服务器版本相对应的手册，以便在booking_end LIKE＆＃39; 2015-06-01％＆＃39;之后使用ASC CASE附近使用正确的语法。那么booking_end A＆＃39;第9行

我希望有人能告诉我我做错了什么。

Answer 1

每个END都需要CASE（还有逗号）：

ORDER BY (CASE WHEN `booking_start`  LIKE ?  THEN `booking_start` END) ASC,
         (CASE WHEN `booking_end`    LIKE ?  THEN `booking_end` END) ASC

Answer 2

@Gordon Linoff

那很有效!!!

SELECT *
FROM `system_booking` 
JOIN `system_address`       ON `system_address`.`address_id` = `system_booking`.`booking_address`
JOIN `system_bookingprice`  ON `system_booking`.`booking_id` = `system_bookingprice`.`bookingprice_link`
JOIN `system_vehicle`       ON `system_vehicle`.`vehicle_id` = `system_booking`.`booking_vehicle`
JOIN `system_parkingfee`    ON `system_booking`.`booking_id` = `system_parkingfee`.`parkingfee_link`
WHERE  (`booking_start` LIKE ? OR `booking_end` LIKE ?) 
ORDER BY 
   (CASE WHEN `booking_start`  LIKE ?  THEN `booking_start`    END) ASC,
   (CASE WHEN `booking_end`    LIKE ?  THEN `booking_end`       END) ASC

谢谢！

MySQL SWITCH CASE多种排序方式

2 个答案: