那么多个值到oracle case语句

Question

有人可以解释如何将多个值传递给oracle case语句然后

SELECT * 
FROM impl_debitor_information 
WHERE soft_delete='F' 
AND SHOP_ID ='4987bc1b-c0a8-6cb7-12f4-0243011f7099' 
AND (debitor_type IS NULL 
     OR debitor_type IN (CASE 
                           WHEN (SELECT techfund_debitor_enabled 
                                 FROM impl_shop 
                                 WHERE shop_id='4987bc1b-c0a8-6cb7-12f4-0243011f7099') = 'YES' THEN ('T','D')                        
                           ELSE 'D'
                         END))

如果值来自 从impl_shop中选择techfund_debitor_enabled，其中shop_id =＆＃39; 4987bc1b-c0a8-6cb7-12f4-0243011f7099＆＃39;是＆＃34;是＆＃34;然后我需要将2个值传递给in子句，如果不是单个值

提前致谢

Answer 1

CASE只返回一个值。您必须重写您的查询。像这样：

SELECT * 
FROM impl_debitor_information i, impl_shop where shop_id s
WHERE d.soft_delete='F' 
AND d.shop_id ='4987bc1b-c0a8-6cb7-12f4-0243011f7099' 
AND d.shop_id = s.shop_id
AND (d.debitor_type IS NULL 
     OR (d.debitor_type IN ('T','D') AND s.techfund_debitor_enabled = 'YES')
     OR (d.debitor_type IN ('D') AND s.techfund_debitor_enabled <> 'YES'))

可能存在错误，我没有测试查询。