我是Groovy和Grails的新手。我使用数据库请求的请求映射使用Spring Security插件开发了一个应用程序。我希望根据角色自定义重定向到主页。
如果用户是ROLE_ADMIN,他将被重定向到他的主页视图adminUser / Homepage.gsp
如果用户是ROLE_USER,他将被重定向到他的主页视图User / Homepage.gsp
根据用户登录信息,我无法获得任何自定义身份验证重定向。
答案 0 :(得分:1)
import org.springframework.security.web.authentication.SavedRequestAwareAuthenticationSuccessHandler
import javax.servlet.http.HttpServletRequest
import javax.servlet.http.HttpServletResponse
import grails.plugin.springsecurity.SpringSecurityUtils
public class MyAuthSuccessHandler extends SavedRequestAwareAuthenticationSuccessHandler
{
@Override
protected String determineTargetUrl(HttpServletRequest request, HttpServletResponse response)
{
def returnUrl = request.getSession().getAttribute('returnUrl')
def roles = SpringSecurityUtils.getPrincipalAuthorities()
for (String role in roles)
{
if (role.equals("ROLE_ADMIN")) {
returnUrl = '/AdminUser/index.gsp'
}
else if (role.equals("ROLE_USER")) {
returnUrl = '/User/index.gsp'
}
else {
returnUrl = '/'
}
}
request.getSession().removeAttribute('returnUrl')
return returnUrl
}
}
这是我的工作代码.... 而是注入一个依赖项我使用SpringSecurityUtils获取当前用户角色并将其重定向到所需的页面...... 谢谢大家的支持。
@ sean3838谢谢你帮助我......
答案 1 :(得分:0)
我就是这样做的。我根据你的需要修改了它。如果有帮助,请告诉我。
在springsecurities中,在auth()方法下的LoginController执行类似这样的操作(在点击登录之前,它将获取用户所在的页面):
def auth() {
session['returnUrl'] = request.getHeader("Referer")
def config = SpringSecurityUtils.securityConfig
if (springSecurityService.isLoggedIn()) {
redirect uri: config.successHandler.defaultTargetUrl
return
}
String view = 'auth'
String postUrl = "${request.contextPath}${config.apf.filterProcessesUrl}"
render view: view, model: [postUrl: postUrl,
rememberMeParameter: config.rememberMe.parameter]
}
现在在src / groovy里面创建一个auth成功处理程序:
package packageName
import org.springframework.security.web.authentication.SavedRequestAwareAuthenticationSuccessHandler
import javax.servlet.http.HttpServletRequest
import javax.servlet.http.HttpServletResponse
public class MyAuthSuccessHandler extends SavedRequestAwareAuthenticationSuccessHandler
{
@Override
protected String determineTargetUrl(HttpServletRequest request, HttpServletResponse response)
{
def returnUrl = request.getSession().getAttribute('returnUrl')
// Get current users role using springSecurityService
// You can inject springSecurityService into this class
// http://stackoverflow.com/questions/6467167/how-to-get-current-user-role-with-spring-security-plugin
if (role == 'ROLE_ADMIN')
{
returnUrl = '/adminUser/Homepage.gsp'
}
else if (role == 'ROLE_USER')
{
returnUrl = '/User/Homepage.gsp'
}
else
{
returnUrl = 'redirect somewhere'
}
request.getSession().removeAttribute('returnUrl')
return returnUrl
}
}
现在在conf / spring / resources.groovy下创建一个像这样的bean:
import grails.plugin.springsecurity.SpringSecurityUtils
// Place your Spring DSL code here
beans = {
authenticationSuccessHandler(packageName.MyAuthSuccessHandler) {
def conf = SpringSecurityUtils.securityConfig
requestCache = ref('requestCache')
defaultTargetUrl = conf.successHandler.defaultTargetUrl
alwaysUseDefaultTargetUrl = conf.successHandler.alwaysUseDefault
targetUrlParameter = conf.successHandler.targetUrlParameter
useReferer = conf.successHandler.useReferer
redirectStrategy = ref('redirectStrategy')
}
}
然后你应该好好去。如果有效,请告诉我。
答案 2 :(得分:0)
您必须在方法之前注入springSecurityService。此外,getAuthorities()应返回一个列表,因此您必须循环它(这是因为人们可以有多个角色)。
import org.springframework.security.web.authentication.SavedRequestAwareAuthenticationSuccessHandler
import javax.servlet.http.HttpServletRequest
import javax.servlet.http.HttpServletResponse
public class MyAuthSuccessHandler extends SavedRequestAwareAuthenticationSuccessHandler
{
def springSecurityService
@Override
protected String determineTargetUrl(HttpServletRequest request, HttpServletResponse response)
{
def returnUrl = request.getSession().getAttribute('returnUrl')
def roles = springSecurityService.getPrincipal().getAuthorities()
for (role in roles)
{
if (role == 'ROLE_ADMIN')
{
returnUrl = '/adminUser/Homepage.gsp'
}
else if (role == 'ROLE_USER')
{
returnUrl = '/User/Homepage.gsp'
}
}
request.getSession().removeAttribute('returnUrl')
return returnUrl
}
}
答案 3 :(得分:0)
假设你的BuildConfig中有这样的一行:
compile ":spring-security-core:2.0-RC4"
以及BootStrap中的一些代码:
def roleAdmin = new Role(authority:LSSRole.ROLE_ADMIN.toString()).save(failOnError: true)
def roleFirm = new Role(authority:LSSRole.ROLE_FIRM.toString()).save(failOnError: true)
def roleLaw = new Role(authority:LSSRole.ROLE_LAWYER.toString()).save(failOnError: true)
def roleFin = new Role(authority:LSSRole.ROLE_FINANCE.toString()).save(failOnError: true)
使用此代码创建示例管理员用户:
UserRole.create admin, roleAdmin, true
以及Config中的一些代码:
'/dbconsole/**': [LSSRole.ROLE_ADMIN.toString()],
'/secure/**': [LSSRole.ROLE_ADMIN.toString()],
'/payment/**': [LSSRole.ROLE_FIRM.toString()],
'/filing/**': [LSSRole.ROLE_FIRM.toString()],
'/finance/**': [LSSRole.ROLE_FINANCE.toString()],
'/lawyer/**': [LSSRole.ROLE_LAWYER.toString()],
其中LSSRole是枚举,有些代码如下:
"/" {
controller = "dispatch"
action = "index"
}
在您的UrlMappings中,用户在成功登录后转移用户,您可以构建这样的调度程序,根据用户的角色将用户分配到不同的目标网页:
class DispatchController {
def index() {
def controller = 'login'
def action = 'auth'
if (SpringSecurityUtils.ifAllGranted(LSSRole.ROLE_ADMIN.toString())) {
controller = 'secure'
action = 'index'
} else if (SpringSecurityUtils.ifAllGranted(LSSRole.ROLE_FINANCE.toString())) {
controller = 'finance'
action = 'index'
} else if (SpringSecurityUtils.ifAllGranted(LSSRole.ROLE_FIRM.toString())) {
controller = 'filing'
action = 'summary'
} else if (SpringSecurityUtils.ifAllGranted(LSSRole.ROLE_LAWYER.toString())) {
controller = 'lawyer'
action = 'index'
} else {
flash.message = 'Where do you think you\'re going? Nno no no'
SecurityContextHolder.clearContext()
}
redirect controller:controller, action:action
}
希望这有帮助。