Question

对于第一次运行，密码将加密字符串。但是如果我想再次循环，我就无法获得加密第二个字符串的密码。

有没有办法在不使用指针的情况下实现这一目标？

#include <iostream>
#include <string>
using namespace std;

char checkSum[63] = "QAZXSWEDCVFRTGBNHYUJMKIOLPqazxswedcvfrtgbnhyujmkiolp1234567890"; //checksum
string message; //original message
string messageEncrypted; //replaces pointer
char YorN;
//int multiplier; //part of the prototype

int main(int argc, char *argz[])
{


    do
    {
        cout << "enter a message to encrypt: ";
        getline(cin, message);
        messageEncrypted = message; //i could use a pointer for this i think but I keep running into problems

        for (unsigned count = 0; count <= messageEncrypted.length(); count++) //cycles through characters in string
        {

            //multiplier = messageEncrypted.length() + (int)messageEncrypted[count]; //declaring prototype
            //messageEncrypted[count] = (int)messageEncrypted[count] * multiplier; //prototyped idea that doesn't work

            while ((int)messageEncrypted[count] > 62) //checks to make sure it is withen the value range of checkSum
            {
                messageEncrypted[count] -= ('A' - 3); //puts it into that range
            }

            messageEncrypted[count] = checkSum[(int)messageEncrypted[count]]; //redeclares character

        }

        cout << "Encrypted message is: \n" << messageEncrypted << endl; //prints out encrypted message
        cout << "\nRun again [y/n] ";
        cin >> YorN;

    } while (YorN == 'y'||YorN=='Y');
    return 0;
}

Answer 1

但是如果我想再次循环，我就无法获得加密第二个字符串的密码。

问题在于，在您使用以下方式阅读用户的回复后：

cin >> YorN;

新行字符仍保留在输入流中。下一次调用getline()只会读取换行符。添加一行以忽略该行的其余部分：

cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');

后立即

cin >> YorN;

简单的密码停止在循环中工作

1 个答案: