我有以下模式和字符串的注册匹配问题。模式基本上是一个名称，后跟任意数量的字符，后跟一个短语（见下面的模式），后跟任意数量的字符，后跟机构名称。
pattern = "[David Maxwell|David|Maxwell] .* [educated at|graduated from|attended|studied at|graduate of] .* Eton College"
str = "David Maxwell was educated at Eton College, where he was a King's Scholar and Captain of Boats, and at Cambridge University where he rowed in the winning Cambridge boat in the 1971 and 1972 Boat Races."
match = re.search(pattern, str)
但是搜索方法返回上面的str不匹配？我的注册表适合吗？我是reg-ex的新手。任何帮助表示赞赏
答案 0 :(得分：5)
[...]表示“来自这组字符的任何字符”。如果你想要“这组单词中的任何单词”，你需要使用括号：(...|...)。
您的表达式中还有另一个问题，即.*（空格，点，星号，空格），这意味着“空格，后跟零个或多个字符，后跟空格”。换句话说，最短的匹配是两个空格。但是，您的文本在“受过教育的”和“伊顿公学”之间只有一个空格。
>>> pattern = '(David Maxwell|David|Maxwell).*(educated at|graduated from|attended|studied at|graduate of).*Eton College'
>>> str = "David Maxwell was educated at Eton College, where he was a King's Scholar and Captain of Boats, and at Cambridge University where he rowed in the winning Cambridge boat in the 1971 and 1972 Boat Races."
>>> re.search(pattern, str)
<_sre.SRE_Match object at 0x1006d10b8>