线程“main”中的异常java.util.ConcurrentModificationException(头第一个java书籍示例)

时间:2015-04-16 19:34:29

标签: java android java.util.concurrent concurrentmodification

我尝试从Head第一版java书 - 第二版(第152页)中运行一个示例。这是一个游戏难题。它以网格中的Dotcoms(字符串)为目标。但是当我试图运行这个谜题时,我遇到了 Java.util.concurrentModificationException 错误。当我试图在网格中找到最后一个dotCom(String)时,我只得到了这个错误。假设我在网格中有三个字符串,如下图所示。因此,当我开始提供输入时,我能够删除(命中)前两个字符串(因为它们在arrayList中添加)但当我尝试删除最后一个字符串(在Arraylist中添加最后一个字符串)时,则得到 concurrentmodificationException < / strong>错误。示例代码和控制台日志如下所示。
那么为什么我会收到此错误以及如何删除此错误。

enter image description here

class DotComBust{

    private GameHelper helper = new GameHelper();
    private ArrayList<DotCom> dotComList = new ArrayList<DotCom>();
    private int numofguesses=0;

    private void setUpGame(){
        DotCom one = new DotCom();
        one.setNames("Pets.com");
        DotCom two = new DotCom();
        two.setNames("eToys.com");
        DotCom three = new DotCom();
        three.setNames("Go2.com");
        dotComList.add(one);
        dotComList.add(two);
        dotComList.add(three);

        System.out.println("your goal is sunk three dot coms");
        System.out.println("Pets.com, eToys.com, Go2.com");
        System.out.println("Try to sink them all in fewest number of guesses");

        for(DotCom dotComToSet : dotComList){
            ArrayList<String> newLocation = helper.placeDotCom(3);
            dotComToSet.setLocationCells(newLocation);
        }

    }

        private void startPlaying(){
            while(!dotComList.isEmpty()){
                String userGuess = helper.getUserInput("Enter a guess");
                checkUserGuess(userGuess);
            }

            finishGame();
        }

        private void checkUserGuess(String userGuess){
            numofguesses++;
            String result = "miss";
            for(DotCom dotComToTest : dotComList){
                result = dotComToTest.checkYourself(userGuess);

                if(result.equals("hit")){
                    break;
                }
                if(result.equals("kill")){
                    dotComList.remove(dotComToTest);
                }
            }
        System.out.println(result);
        }


        private void finishGame(){
            System.out.println("All the dotcoms are dead your stock is worthless");
            if(numofguesses<=18){
                System.out.println("It only took you" + numofguesses + "guesses");
                System.out.println("You got out before your option sank");

            }else{
                System.out.println("Took you long enough" + numofguesses + "guesses");
                System.out.println("Fish are dancing with your option");
            }
        }

        public static void main(String[] args) {
            DotComBust game = new DotComBust();
            game.setUpGame();
            game.startPlaying();
        }

}

错误

Exception in thread "main" java.util.ConcurrentModificationException
at java.util.ArrayList$Itr.checkForComodification(Unknown Source)
at java.util.ArrayList$Itr.next(Unknown Source)
at DotComBust.checkUserGuess(DotComBust.java:77)
at DotComBust.startPlaying(DotComBust.java:68)
at DotComBust.main(DotComBust.java:106)

2 个答案:

答案 0 :(得分:1)

我假设你可能有另一个同时运行的绘图线程?

在这种情况下,使用名为List的{​​{1}}的线程安全实现:

CopyOnWriteArrayList

答案 1 :(得分:0)

因为在循环收集时

 while(!dotComList.isEmpty()){
            String userGuess = helper.getUserInput("Enter a guess");
            checkUserGuess(userGuess);
 }

您不能修改列表的内容,但在您的方法 checkUserGuess 中,您试图从列表中删除元素

if(result.equals("kill")){
                    dotComList.remove(dotComToTest);
}

这是导致ConcurrentModificationException

的原因