那是我的代码:
override func keyDown(theEvent: NSEvent) {
super.keyDown(theEvent)
switch theEvent.character {
case NSLeftArrowFunctionKey:
println(1)
case NSRightArrowFunctionKey:
println(2)
case NSDownArrowFunctionKey:
println(3)
case NSUpArrowFunctionKey:
println(4)
default:
break
}
}
正如你所看到的,我试图识别是否按下了一个箭头按钮,但它永远不会起作用。甚至似乎也没有调用函数keyDown。
这是viewDidAppear
中的内容,如果这可以帮助您提供答案:
override func viewDidAppear() {
super.viewDidAppear()
self.view.window?.styleMask = NSClosableWindowMask | NSMiniaturizableWindowMask | NSTitledWindowMask
var frame = self.view.window?.frame
var newHeight = CGFloat(438)
var newWidth = CGFloat(415)
frame?.size = NSMakeSize(newWidth, newHeight)
self.view.window?.setFrame(frame!, display: true)
self.view.window?.backgroundColor = NSColor.darkGrayColor()
}
在viewDidLoad
我只是添加了一些不可选择且不可编辑的NSTextField:
var x = CGFloat(0)
var y = CGFloat(0)
var tag = 1
for var i = 0; i < 4; i++ {
for var j = 0; j < 4; j++ {
var tile = NSTextField(frame: NSRect(x: x, y: y, width: 100, height: 100))
tile.enabled = false
tile.stringValue = ""
tile.font = NSFont(name: "Helvetica", size: 75)
tile.backgroundColor = NSColor.lightGrayColor()
tile.editable = false
tile.selectable = false
tile.drawsBackground = true
tile.alignment = NSTextAlignment(rawValue: 2)!
tile.tag = tag
x += 105
ar.append(tile)
self.view.addSubview(tile)
tag++
}
x = 0
y += 105
}
我只是不知道keyDown
为什么不起作用,所以我真的很感激任何帮助。
修改
全班代码:
import Cocoa
import AppKit
import Foundation
class _048Main: NSViewController {
var ar : Array<NSTextField> = []
var left = 0
var dict : Dictionary<Int, NSColor> = [:]
var pic2 = NSColor.redColor()
var pic4 = NSColor.whiteColor()
var pic8 = NSColor.orangeColor()
var pic16 = NSColor.magentaColor()
var pic32 = NSColor()
var pic64 = NSColor()
var pic128 = NSColor()
var pic256 = NSColor() // Some colors will be added
var pic512 = NSColor()
var pic1024 = NSColor()
var pic2048 = NSColor()
override func viewDidLoad() {
super.viewDidLoad()
dict[2] = pic2
dict[4] = pic4
dict[8] = pic8
dict[16] = pic16
dict[32] = pic32
dict[64] = pic64
dict[128] = pic128
dict[256] = pic256
dict[512] = pic512
dict[1024] = pic1024
dict[2048] = pic2048
var x = CGFloat(0)
var y = CGFloat(0)
var tag = 1
for var i = 0; i < 4; i++ {
for var j = 0; j < 4; j++ {
var tile = NSTextField(frame: NSRect(x: x, y: y, width: 100, height: 100))
tile.enabled = false
tile.stringValue = ""
tile.font = NSFont(name: "Helvetica", size: 75)
tile.backgroundColor = NSColor.lightGrayColor()
tile.editable = false
tile.selectable = false
tile.drawsBackground = true
tile.alignment = NSTextAlignment(rawValue: 2)!
tile.tag = tag
x += 105
ar.append(tile)
self.view.addSubview(tile)
tag++
}
x = 0
y += 105
}
left = 16
generateTile()
generateTile()
}
func generateTile() {
var r = Int(arc4random_uniform(UInt32(left)))
var tmp = 0
for var i = 0; i < 16; i++ {
if ar[i].stringValue == "" {
if tmp == r {
var t = Int(arc4random_uniform(10))
switch t {
case 0...1:
ar[i].stringValue = "2"
ar[i].backgroundColor = pic2
default:
ar[i].stringValue = "4"
ar[i].backgroundColor = pic4
}
left--
break
}
tmp++
}
}
}
override func viewDidAppear() {
super.viewDidAppear()
self.view.window?.styleMask = NSClosableWindowMask | NSMiniaturizableWindowMask | NSTitledWindowMask
var frame = self.view.window?.frame
var newHeight = CGFloat(438)
var newWidth = CGFloat(415)
frame?.size = NSMakeSize(newWidth, newHeight)
self.view.window?.setFrame(frame!, display: true)
self.view.window?.backgroundColor = NSColor.darkGrayColor()
}
override func keyDown(theEvent: NSEvent) {
super.keyDown(theEvent)
switch theEvent.character {
case NSLeftArrowFunctionKey:
println(1)
case NSRightArrowFunctionKey:
println(2)
case NSDownArrowFunctionKey:
println(3)
case NSUpArrowFunctionKey:
println(4)
default:
super.mouseDown(theEvent)
}
}
}
答案 0 :(得分:2)
试试此代码
ResourceBundle resource = ResourceBundle.getBundle("test");
String VALUE1=resource.getString("KEY1");
String VALUE2=resource.getString("KEY2");
答案 1 :(得分:1)
你的应用甚至可以构建吗?
NSEvent
个实例没有character
属性,他们拥有characters
属性。使用character
会导致构建失败并且Xcode出现错误消息。更多characters
返回可选String
而switch
个案例属于Int
类型 - 此类型不匹配也会导致构建失败。
根据我的经验,找出是否按下任何箭头键的最简单方法是打开事件的keyCode
属性。
import Foundation
import Cocoa
let kLeftArrowKeyCode: UInt16 = 123
let kRightArrowKeyCode: UInt16 = 124
let kDownArrowKeyCode: UInt16 = 125
let kUpArrowKeyCode: UInt16 = 126
class ViewController: NSViewController {
override func keyDown(theEvent: NSEvent) {
switch theEvent.keyCode {
case kLeftArrowKeyCode:
println(1)
case kRightArrowKeyCode:
println(2)
case kDownArrowKeyCode:
println(3)
case kUpArrowKeyCode:
println(4)
default:
break
}
}
}
如果您愿意,您仍然可以使用预定义的常量,但这些代表Unicode代码,因此在您开启characters
之前,您需要先将它们转换为字符串。
答案 2 :(得分:1)
您只需使用隐形按钮即可。首先在窗口中添加一个方形按钮。为其分配所需的密钥。使您的按钮宽0像素,高0像素。将IBAction添加到按钮,并在用户按下键时执行代码。
另一个选项是addLocalMonitorForEventsMatchingMask以获取更多信息,请查看此链接
答案 3 :(得分:1)
忽略有关转换字符等的额外内容,如果您的keyDown()
功能即使被调用,最可能的原因是您没有告诉操作系统您的视图可以接受关键事件(通过覆盖acceptsFirstResponder
)。
在视图类中执行此操作:
override var acceptsFirstResponder: Bool { get { return true } }