我正在努力使用HttpURLConnection和OutputStreamWriter。
代码实际到达服务器,因为我收到了有效的错误 回复。发出了POST请求,但没有收到任何数据 服务器端。
非常感谢任何正确使用此内容的提示。
代码在AsyncTask
中protected JSONObject doInBackground(Void... params) {
try {
url = new URL(destination);
client = (HttpURLConnection) url.openConnection();
client.setDoOutput(true);
client.setDoInput(true);
client.setRequestProperty("Content-Type", "application/json; charset=UTF-8");
client.setRequestMethod("POST");
//client.setFixedLengthStreamingMode(request.toString().getBytes("UTF-8").length);
client.connect();
Log.d("doInBackground(Request)", request.toString());
OutputStreamWriter writer = new OutputStreamWriter(client.getOutputStream());
String output = request.toString();
writer.write(output);
writer.flush();
writer.close();
InputStream input = client.getInputStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(input));
StringBuilder result = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
result.append(line);
}
Log.d("doInBackground(Resp)", result.toString());
response = new JSONObject(result.toString());
} catch (JSONException e){
this.e = e;
} catch (IOException e) {
this.e = e;
} finally {
client.disconnect();
}
return response;
}
我想发送的JSON:
JSONObject request = {
"action":"login",
"user":"mogens",
"auth":"b96f704fbe702f5b11a31524bfe5f136efea8bf7",
"location":{
"accuracy":25,
"provider":"network",
"longitude":120.254944,
"latitude":14.847808
}
};
我从服务器得到的回复:
JSONObject response = {
"success":false,
"response":"Unknown or Missing action.",
"request":null
};
我应该得到的回应:
JSONObject response = {
"success":true,
"response":"Welcome Mogens Burapa",
"request":"login"
};
服务器端PHP脚本:
<?php
$json = file_get_contents('php://input');
$request = json_decode($json, true);
error_log("JSON: $json");
error_log('DEBUG request.php: ' . implode(', ',$request));
error_log("============ JSON Array ===============");
foreach ($request as $key => $val) {
error_log("$key => $val");
}
switch($request['action'])
{
case "register":
break;
case "login":
$response = array(
'success' => true,
'message' => 'Welcome ' . $request['user'],
'request' => $request['action']
);
break;
case "location":
break;
case "nearby":
break;
default:
$response = array(
'success' => false,
'response' => 'Unknown or Missing action.',
'request' => $request['action']
);
break;
}
echo json_encode($response);
exit;
?>
Android Studio中的logcat输出:
D/doInBackground(Request)﹕ {"action":"login","location":{"accuracy":25,"provider":"network","longitude":120.254944,"latitude":14.847808},"user":"mogens","auth":"b96f704fbe702f5b11a31524bfe5f136efea8bf7"}
D/doInBackground(Resp)﹕ {"success":false,"response":"Unknown or Missing action.","request":null}
如果我将?action=login
附加到URL
,我可以从服务器获得成功回复。但只有 action 参数注册服务器端。
{"success":true,"message":"Welcome ","request":"login"}
结论必须是URLConnection.write(output.getBytes("UTF-8"));
嗯,毕竟数据会被转移。
@greenaps提供的解决方案可以解决问题:
$json = file_get_contents('php://input');
$request = json_decode($json, true);
上面更新了PHP脚本以显示解决方案。
答案 0 :(得分:6)
echo (file_get_contents('php://input'));
将显示json文本。使用它像:
$jsonString = file_get_contents('php://input');
$jsonObj = json_decode($jsonString, true);
答案 1 :(得分:1)
尝试使用DataOutputStream而不是OutputStreamWriter。
DataOutputStream out = new DataOutputStream(_conn.getOutputStream());
out.writeBytes(your json serialized string);
out.close();
答案 2 :(得分:1)
我已经让服务器告诉我它是从我那里得到的。
请求标头和POST正文
<?php
$requestHeaders = apache_request_headers();
print_r($requestHeaders);
print_r("\n -= POST Body =- \n");
echo file_get_contents( 'php://input' );
?>
像魅力一样工作)
答案 3 :(得分:0)
代码实际上到达了服务器,因为我确实收到了有效的错误 回应回来。发出了POST请求,但未接收到数据 服务器端。
也遇到了同样的情况,并来@greenapps回答。 您应该知道从“发布请求”中收到了什么服务器
我首先要在服务器端执行的操作:
echo (file_get_contents('php://input'));
然后在客户端打印/祝酒/显示消息响应。确保其正确格式,例如:
{"username": "yourusername", "password" : "yourpassword"}
如果这样的响应(因为您使用yourHashMap.toString()
发布了请求):
{username=yourusername,password=yourpassword}
而不是使用.toString(),而是使用此方法将HashMap转换为String:
private String getPostDataString(HashMap<String, String> postDataParams) {
StringBuilder result = new StringBuilder();
boolean first = true;
for (Map.Entry<String,String> entry : postDataParams.entrySet()){
if(first){
first = false;
}else{
result.append(",");
}
result.append("\"");
result.append(entry.getKey());
result.append("\":\"");
result.append(entry.getValue());
result.append("\"");
}
return "{" + result.toString() + "}";
}