Question

鉴于我有以下哈希数组

@response =  { "0"=>{"forename_1"=>"John", "surname_1"=>"Smith"}, 
               "1"=>{"forename_1"=>"Chris", "surname_1"=>"Jenkins"}, 
               "2"=>{"forename_1"=>"Billy", "surname_1"=>"Bob"},
               "Status" => 100
             }

我希望创建一个forename_1和surname_1值组合在一起的数组，因此所需的输出将是

["John Smith", "Chris Jenkins", "Billy Bob"]

所以我可以做到这一点，但需要进一步的帮助

# Delete the Status as not needed
@response.delete_if { |k| ["Status"].include? k }

@response.each do |key, value|
  puts key
  #This will print out 0 1 2
  puts value
  # This will print {"forename_1"=>"John", "surname_1"=>"Smith"}, "{"forename_1"=>"Chris", "surname_1"=>"Jenkins"}, "{"forename_1"=>"Billy", "surname_1"=>"Bob"}
  puts value.keys
 # prints ["forename_1", "surname_1"], ["forename_1", "surname_1"], ["forename_1", "surname_1"] 
  puts value.values
  # prints ["John", "Smith"], ["Chris", "Jenkins"], ["Billy", "Bob"] 
  value.map { |v| v["forename_1"] }
  # However i get no implicit conversion of String into Integer error
end

我在这里做错了什么？

由于

Answer 1

另一种方式：

@response.values.grep(Hash).map { |t| t.values.join(' ')}

Answer 2

@response.values.map{ |res| 
   [res["forename_1"] , res["surname_1"]].join(' ')  if res.is_a?(Hash)  
}.compact

Answer 3

你需要做的是获取@response哈希的值，过滤掉不是Hash的实例，然后将名字和姓氏连在一起，我会做点什么像这样：

@response.values.grep(Hash).map { |h| "#{h['forename_1']} #{h['surname_1']}" }
# => ["John Smith", "Chris Jenkins", "Billy Bob"]

从哈希数组中提取数据Ruby

3 个答案: