如何以科学记数法最好地打印2个浮点数但具有相同的指数? 例如:我想打印这样的数字:
1.234e-6
11.234e-6
我想要一些功能来自动检测最佳指数 - 较小的数字始终从第一个十进制数字开始,较大的数字打印它必须具有相同的指数。 例如:0.1和100将打印
1.000e-1
1000.000e-1
但即使我明确要求2位小数String.format("%2.3e",11.234e-6)
,我也得到1.123e-5
答案 0 :(得分:1)
到目前为止,我提出了以下代码。它按我的意愿工作。但正如你所看到的那样,它并不是简短或快速......如果有人指出一些Java原生函数可以帮助我做得更优雅,那就太好了......
public static String repeat(int count, String with) {
if(count<0){
return "";
}
if(count>1e5){
return "";
}
return new String(new char[count]).replace("\0", with);
}
public static String getFormattedDouble(double num,int posInt,int posFrac){
if(num == 0) return "0"; // correct 0 value to be print only with one 0
String sInt = repeat(posInt,"0");
String sFrac = repeat(posFrac,"0");
String sSing = num<0 ? "" : "+";
DecimalFormat form = new DecimalFormat(sSing+sInt+"."+sFrac+"E0");
String s = form.format(num);
s = s.replace("E","e"); // I really thing capital E looks ugly
return s;
}
public static String[] get2doublesSameExp(double a, double b){
String[] s = new String[2];
int expA;
if(a == 0) expA = 0;
else expA = (int)Math.floor(Math.log10(Math.abs(a)));
int expB;
if(b == 0) expB = 0;
else expB = (int)Math.floor(Math.log10(Math.abs(b)));
double expDif = Math.abs((double)expA-(double)expB);
int fractPos = 3;
if(expDif > 4) fractPos = 1; // too big exponent difference reduce fraction digits
if(expDif > 6){
// too big exponent difference print it normally it will be nicer
s[0] = String.format("%1.3e",a);
s[1] = String.format("%1.3e",b);
return s;
}
int minExp = Math.min(expA,expB) - 1;
s[0] = getFormattedDouble(a, expA - minExp, fractPos );
s[1] = getFormattedDouble(b, expB - minExp, fractPos );
// just text right justification
String rightJust = repeat((int)expDif," ");
int justIdx = expA < expB ? 0 : 1;
s[justIdx] = rightJust + s[justIdx];
return s;
}
String[] s = get2doublesSameExp(1.234e-6,11.234e-6);