Question

我正在构建一个超级简单的网站应用程序，该应用程序调用API来检索用户输入到所述应用程序的任何网站的反向链接数据。 API发送的数据包括字符串（例如http://www.domain.com/?feed=rss）和数字，并且采用JSON格式。我按如下方式解析响应：

mozResponse = JSON.parse(response);

然后我遍历这些数据，只将我想要的数据推送到2个新数组（arry，arry1），声明如下：

arry = []; 
arry1 = [];

推动如下：

arry.push({id:i, url:mozResponse[i].uu, pa:Math.round(mozResponse[i].upa), da:Math.round(mozResponse[i].pda), anchor:mozResponse[i].lt});

然后按如下方式对这两个数组进行Stringify：

    var cautionArrayString = JSON.stringify(arry);
    var dangerArrayString = JSON.stringify(arry1);

我使用JavaScript XMLHTTPRequest将此数据发布到php文件，如下所示：

var queryString = "email=" + Email + "&caution=" + cautionArrayString + "&danger=" + dangerArrayString;
xhr1.onreadystatechange=Response1;
xhr1.open("post","http://example.com/emails.php",true);
xhr1.setRequestHeader("Content-type","application/x-www-form-urlencoded");
xhr1.send(queryString);

然后php文件显示：

$caution = $_POST['caution']; 
$danger = $_POST['danger'];

我知道在这一点上我应该在最初这样做时再次解码JSON我最终得到了一个破碎的数组。这是console.log在将数据发布到php文件之后读取的内容，使用php文件：

echo($_POST['caution']);
echo ($_POST['danger']);

Console.log显示：

[{"id":3,"url":"example.ca/","pa":26,"da":12,"anchor”:”Example”},    
{"id":4,"url":"example.ca/","pa":26,"da":12,"anchor":"thank you gifts"},  
{"id":5,"url":"example.ca/","pa":26,"da":12,"anchor":"flowers"},
{"id":6,"url":"example.ca/","pa":26,"da":12,"anchor":"thank you"},
{"id":7,"url":"example.ca/","pa":26,"da":12,"anchor":"Arrive in Style"},
{"id":8,"url":"example.ca/","pa":26,"da":12,"anchor":"dignity"},
{"id":9,"url":"example.ca/","pa":26,"da":12,"anchor":"Beautiful in Blue"},
{"id":10,"url":"example.ca/","pa":26,"da":12,"anchor":"Blooming Garden Basket"},
{"id":11,"url":"example.ca/","pa":26,"da":12,"anchor":"Country Basket Blooms"},
{"id":12,"url":"example.ca/","pa":26,"da":12,"anchor":"Heart’s Delight"},
{"id":13,"url":"example.ca/","pa":26,"da":12,"anchor":"Make a Wish"},
{"id":14,"url":"example.ca/","pa":26,"da":12,"anchor":"Moondance"},
{"id":15,"url":"example.ca/","pa":26,"da":12,"anchor":"Queen’s Court"},
{"id":16,"url":"example.ca/","pa":26,"da":12,"anchor":"Sweet as Sugar"},
{"id":17,"url":"example.ca/","pa":26,"da":12,"anchor":"flower colors"},
{"id":18,"url":"example.ca/","pa":26,"da":12,"anchor":"Always Yours"},
{"id":19,"url":"example.ca/","pa":26,"da":12,"anchor":"Sunrise, Sunset"},
{"id":20,"url":"example.ca/","pa":26,"da":12,"anchor":"Uniquely Chic"},
{"id":21,"url":"example.com/best/index.php?page=1998","pa":25,"da":31,"anchor":"example.ca/"},
{"id":22,"url":"example.com/best/index.php?page=1994","pa":25,"da":31,"anchor":"example.ca/"},
{"id":23,"url":"example.ca/","pa":25,"da":16,"anchor”:”example”},
{"id":28,"url":"example.ca/article/156-best-cms-for-small-business","pa":22,"da":39,"anchor":"example.ca/"},
{"id":30,"url":"example.ca/blog.html","pa":21,"da":15,"anchor":"example.ca/"},
{"id":31,"url":"example.ca/beyond-the-flowers-choosing-a-vase/","pa":20,"da":12,"anchor”:”Example”},
{"id":32,"url":"example.ca/beyond-the-flowers-choosing-a-vase/","pa":20,"da":12,"anchor":"Arrive in Style"},
{"id":33,"url":"example.ca/beyond-the-flowers-choosing-a-vase/","pa":20,"da":12,"anchor":"Beautiful in Blue"},
{"id":34,"url":"example.ca/beyond-the-flowers-choosing-a-vase/","pa":20,"da":12,"anchor":"Blooming Garden Basket"},
{"id":35,"url":"example.ca/beyond-the-flowers-choosing-a-vase/","pa":20,"da":12,"anchor":"Country Basket Blooms"},
{"id":36,"url":"example.ca/beyond-the-flowers-choosing-a-vase/","pa":20,"da":12,"anchor":"Heart’s Delight"},
{"id":37,"url":"example.ca/beyond-the-flowers-choosing-a-vase/","pa":20,"da":12,"anchor":"Make a Wish"},
{"id":38,"url":"example.ca/gifts.html","pa":19,"da":11,"anchor”:”example- <span class=\"catlist\"> Flowers</span>"},
{"id":39,"url":"example.ca/category/flowers/","pa":19,"da":16,"anchor”:”Example”},
{"id":40,"url":"example.ca/category/floral-fauna/","pa":19,"da":16,"anchor”:”Example”},
{"id":41,"url":"nunavut.findstuffhere.ca/nunavut/?feed=rss2[]

你可以在那里看到第一个数组是不完整的，第二个是空的（应该是！）。所以我的问题是，导致这种情况的原因是什么？如何解决？

注意事项

我使用3个URL作为测试输入。数据包含1个URL，但其他2个（包括上面的示例）返回这个不完整的JSON，似乎是因为查询字符串是从API返回的URL的一部分？
我console.log(mozResponse)，输出符合预期
I console.log(arry) and console.log(arry1)迭代通过mozResponse并将数据从mozResponse推送到arry / arry1并且输出是一个完整的数组
我console.log(arry)和console.log(arry1)应用JSON.stringify之后但是在发布到php并且输出完成之后

我探索过的事情

我原本以为这是其中一个网址的结果 API返回包括查询字符串（例如？feed = rss2）但是在此断点之前有查询字符串处理得很好
我使用的似乎不是JSON错误 json_last_error（）;它返回0.
也似乎不是一个 JSON / POST char限制因为它在我返回破坏的JSON时输入不同的URL（此URL的$ _POST输出也是如此在查询字符串后面断开，不确定这是否巧合）
Suhosin不在场
创建了一个phpinfo页面来检查max_vars但是限制很大

非常感谢任何帮助！

*不同的引用来自复制/粘贴！

Answer 1

您可能只需要编码您的值以便在查询字符串中使用：

var cautionArrayString = encodeURIComponent(JSON.stringify(arry));
var dangerArrayString = encodeURIComponent(JSON.stringify(arry1));

var queryString = "email=" + encodeURIComponent(Email) + "&caution=" + cautionArrayString + "&danger=" + dangerArrayString;

将其转换为json不会自动对其进行正确编码以在url中使用，因此值中的字符可能会破坏查询字符串。

假设不同的引号是由复制粘贴引起的......

在php中以不完整的格式接收JSON数据？

1 个答案: