如何使用PHP在Database中存储文本文件的内容

时间:2015-04-16 09:20:20

标签: php html mysql sql

//输出开始

输出文件:-05012015.txt

  This is of my output of file which is the mapper file used for the verification But all below no are store in the database .That No Description  are as follow


            34012015000180001000631931058620000607262Y22122014 N                   


Above All Digits- 34 :-Contant value
                  01201500018 :-record number 
                  0001000631931058620 :-Doc No
                  000607262 :-Product Code
                  Y :-status
                  22122014 :date format DD/MM/YYYY
                    :-one Blank Space
                  N :- Status
                    :-Remaining Blank Spaces

Above Description of record which store different column in the database...

//Output End

当文本文件显示内容时,包含所有no,字符,空格和其他记录空格的内容在存储在不同列中的文件中结束。

当我点击第二个提交按钮然后将数据存储在Mysql数据库中 我想在mysql数据库中存储文本文件的所有内容,包括所有no,字符,空格和其他记录空格。

PHP& HTML代码: -

        Below is the my PHP with HTMl Code 

        <html>
        <style>
        span{color: #FF0000;}
        </style>
        <body>
        <script type="text/javascript">
        function validate()
        {
        if( document.myForm.photo.value == "" )
           {
             alert( "Please Upload File!" );
             document.myForm.photo.focus();
             return false;
           }
            return( true );
        }
        </script>
        <form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" enctype="multipart/form-data" name="myForm" onsubmit="return(validate());">
        Attach Mapper File:-<input type="file" name="photo" size="140"> <span>[Select Only  .TXT fle]</span>&nbsp;&nbsp;&nbsp;
         <input type="submit" name="submit" value="Submit">&nbsp;&nbsp;&nbsp;
        <br ><br> <br> 

        </form>

        </body>
        </html>

        ===================================================================================================================================================
        <b>File Name:-&nbsp;&nbsp;&nbsp;<?php
        // escape variables for security
              $pic=( $_FILES['photo']['name']);
         echo basename($pic) . "<br/>";?><br> 
        File Description:-</b><br><br><br> 

        <?php

        $file=fopen ("test/$pic","r") or exit("Error");
        $data="";

        while(!feof($file))
        {

          $data .= "<pre>" . fgets($file) . "<br/>";
        }

        fclose($file);
        echo $data;

        ?>
        =====================================================================================================================================================================
        <html>
        <body>
         <form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
         <input type="submit" name="submit2" value="Submit">&nbsp;&nbsp;&nbsp;
        </form>
        </body>
        </html>

//Code End

Mysql表语法: -

CREATE TABLE test(
id int(5) NOT NULL AUTO_INCREMENT,
no1 varchar(40)  NOT NULL,
no2 varchar(40),
no3 varchar(40),
no4 varchar(40),
no5 varchar(40),
no6 varchar(40),
no7 varchar(40),
no8 varchar(40),
no9 varchar(40),
PRIMARY KEY (id))
engine=InnoDB;

1 个答案:

答案 0 :(得分:1)

只需将内容存储在变量&amp;然后使用MySQL查询将其存储在数据库中。

这样做:

$content = file_get_content('Your File');
$query = "INSET INTO table (field) VALUES ('".$content."')";

让我知道更多帮助!