我可以在屏幕上显示图像,但我想使用session显示图像。请帮助我。
$_SESSION['user_name6'] = $_FILES["file"]["name"];
if(isset($_SESSION['user_name6']))
{
echo "<img src=<?php echo $_SESSION[user_name6]; ?> width=300 height=400
alt=Image path Invalid name=image />";
}
else
{
print "no pic here";
}
答案 0 :(得分:1)
我不知道你会做什么,但这是最适合的方法
当您在表单中放置文件类型时,需要使用全局变量Files
<强> form.html 强>
<form action="process.php" method="post" enctype="multipart/form-data">
<label for="picture">Picture:</label>
<input type="file" name="picture" id="picture"><br>
<input type="submit" name="submit" value="Upload">
</form>
<强> process.php 强>
<?php
session_start();
//make sure you have created the **upload** directory
$filename = $_FILES["picture"]["tmp_name"];
$destination = "upload/" . $_FILES["picture"]["name"];
move_uploaded_file($filename, $destination); //save uploaded picture in your directory
$_SESSION['user_name6'] = $destination;
header('Location: display_picture.php');
<强> display_picture.php 强>
<?php
session_start();
?>
<div>
<img src="<?php echo $_SESSION['user_name6']; ?>" alt="picture"/>
</div>