如何摆脱这些警告？

Question

#include <iostream>
 #include "Pizza.h"

int main() {

 iFood* food;

food = new Pizza(14.0, 8);

 for (int i = 0; i < 3; i++)
     food->consume();
 food->display();
 std::cout << std::endl;

 delete food;

 food = new DeluxePizza(12.0, 6, "mushrooms, peppers");

 for (int i = 0; i < 2; i++)
     food->consume();
 food->display();
 std::cout << std::endl;

 delete food;
 }

这是我的main.cpp 当我运行这段代码时，它显示了在iFood上调用的删除警告，它是抽象的，但是具有非虚拟析构函数。

Answer 1

您需要在virtual中创建析构函数iFood。

请参阅Why do we need a pure virtual destructor in C++?了解原因。