比较两组之间的每个元素？

Question

我试图比较两组数据

set1 = [a,b,c,d,e,f] set2 = [a,c,e]

我如何找出set2中set1中的哪个变量，然后将其输出到另一个显示结果的集合？

Answer 1

使用intersection：

set2.intersection(set1)

如果您确实有列表，请set(set2).intersection(set1)。

根据你的评论可能是一个字典，其中值是布尔值，基于set1中的每个元素是否在交集中：

set1 = ["a","b","c","d","e","f"]
set2 = ["a","c","e"]

inter = set(set2).intersection(set1)

vals = {k:k in inter for k in set1}

print(vals)
{'a': True, 'c': True, 'b': False, 'e': True, 'd': False, 'f': False}

如果你想要的只是一个映射，那么从set2创建一个集就足够了：

set1 = ["a","b","c","d","e","f"]
set2 = ["a","c","e"]

st2 = set(set2)

vals = {k: k in st2 for k in set1}

或者为共同和不同的元素获得两组：

st2 = set(set2)

inter = st2.intersection(set1)

diff = st2.difference(set1)