如何创建一个宏来定义clojure中的两个函数

Question

以下代码的行为与我的预期不符。

; given a function name, its args and body, create 2 versions:
; i.e., (double-it foo []) should create 2 functions: foo and foo*
(defmacro double-it             
  [fname args & body]       
  `(defn ~fname ~args ~@body) 
  `(defn ~(symbol (str fname "*")) ~args ~@body))

上面的代码没有像我期望的那样创建两个函数。它只会创建最后一个。

user=> (double-it deez [a b] (str b a))
#'user/deez*

如何让一个宏定义两个函数？

Answer 1

; given a function name, its args and body, create 2 versions:
; ie (double-it foo [] ) should create 2 functions: foo and foo*
(defmacro double-it                
  [fname args & body]         
  `(do (defn ~fname ~args ~@body)
       (defn ~(symbol (str fname "*")) ~args ~@body)))

(double-it afunc [str] (println str))

(afunc* "asd")
(afunc "asd")

无需单独引用它们。