Question

我有一个数组：

[{"stammkost":"IWXI","call":"name1","ean":"802.6180.222","number":"5"},{"stammkost":"8566","call":"name2","ean":"657.7121.393","number":"5"}]

我想像这样为它中的每个Object发送一个PHP-Call（使用asynctask for it。这有一个原因不正确.Asynctask应该为数组中的每个对象执行，对吧？但它只会得到第一次执行，或者最后一次像logcat一样。表名是正确的，但很明显asynctask没有正确执行..你能帮助我吗？

logcat的：

04-15 21:01:54.207: V/Button(3938): Send
04-15 21:01:54.207: V/stammkost(3938): IWXI
04-15 21:01:54.207: V/tablename(3938): IWAA_IWXI_15.04.2015
04-15 21:01:54.207: V/stammkost(3938): 8566
04-15 21:01:54.207: V/tablename(3938): IWAA_8566_15.04.2015
04-15 21:01:54.207: V/jsArray(3938): [{"ean":"802.6180.222","number":"5"},{"ean":"657.7121.393","number":"5"}]
04-15 21:01:54.407: D/CreateMovementAsyncTask(3938): CREATE TABLE `IWAA_8566_15.04.2015` (uid int(11) primary key auto_increment, unique_id varchar(23) not null unique, ean varchar(20) not null, number varchar(6) not null,accepted varchar(1) not null) comment='{"out_user":"pb","out_email":"test@test.com","out_date":"15.04.2015"}'1
04-15 21:01:54.447: D/CreateMovementAsyncTask(3938): CREATE TABLE `IWAA_8566_15.04.2015` (uid int(11) primary key auto_increment, unique_id varchar(23) not null unique, ean varchar(20) not null, number varchar(6) not null,accepted varchar(1) not null) comment='{"out_user":"pb","out_email":"test@test.com","out_date":"15.04.2015"}'MYSQL Error: Table 'IWAA_8566_15.04.2015' already exists

功能：

private void CreateMovement(){
     for (int i = 0; i < GlobalClass.jsArrayGeraete.length(); i++) {
         try {
            JSONObject jsonObj = GlobalClass.jsArrayGeraete.getJSONObject(i);
            GlobalClass.KOST_NEW = jsonObj.getString("stammkost");
            GlobalClass.tablename = SelectKostActivity.KOST + "_" + GlobalClass.KOST_NEW + "_" + GlobalClass.date;
            new CreateMovementAsyncTask().execute();
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

      }
}

和AsyncTask：

class CreateMovementAsyncTask extends AsyncTask<Void,Void,Void>{
    protected Void doInBackground(Void... arg0) {
        DBFunctions DBFunction = new DBFunctions();
        try {
            JSONObject jObjComment = new JSONObject();
            jObjComment.put("out_user", LoginActivity.name);
            jObjComment.put("out_email", GlobalClass.email);
            jObjComment.put("out_date", GlobalClass.date);
            String json = DBFunction.create_movement(GlobalClass.tablename,jObjComment.toString());
            Log.d("CreateMovementAsyncTask", json);
        } catch (JSONException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        }


        return null;
    }

    protected void onPostExecute(Void json){

    }
}

编辑：

public String create_movement(String tablename, String comment){
    // Building Parameters      
    //Log.e("tablename", tablename);
    //Log.e("comment", comment);
    List<NameValuePair> params = new ArrayList<NameValuePair>();
    params.add(new BasicNameValuePair("tag", "create_movement"));
    params.add(new BasicNameValuePair("tablename", tablename));
    params.add(new BasicNameValuePair("comment", comment));
    ServiceHandler jsonStr = new ServiceHandler();
    String json = jsonStr.makeServiceCall(requesteanURL, ServiceHandler.POST, params);
return json;

PHP：

else if ($tag == 'create_movement') {
            $coni=mysqli_connect("localhost","LOGIN","PW","movement");
            $tablename = $_POST['tablename'];
            $comment = $_POST['comment'];
            //$jcomment = json_decode($comment, true);
            $sql = "CREATE TABLE `" .$tablename. "` (uid int(11) primary key auto_increment, unique_id varchar(23) not null unique, ean varchar(20) not null, betriebszahl varchar(6) not null,accepted varchar(1) not null) comment='".$comment."'";           
            echo $sql;
            $result = mysqli_query($coni, $sql) or die("Query failed : " . mysqli_error($coni));
            echo $result;

Answer 1

编辑：我认为GlobalClass.tablename可能与多个AsyncTask实例不同步。

尝试通过varargs传递参数，这是一个例子：

private void CreateMovement(){
     for (int i = 0; i < GlobalClass.jsArrayGeraete.length(); i++) {
         try {
            JSONObject jsonObj = GlobalClass.jsArrayGeraete.getJSONObject(i);
            GlobalClass.KOST_NEW = jsonObj.getString("stammkost");
            //GlobalClass.tablename = SelectKostActivity.KOST + "_" + GlobalClass.KOST_NEW + "_" + GlobalClass.date;
            String tableName = SelectKostActivity.KOST + "_" + GlobalClass.KOST_NEW + "_" + GlobalClass.date;

            //pass in the table name and data
            new CreateMovementAsyncTask().execute(tableName,  GlobalClass.email,  GlobalClass.date);
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

      }
}

在AsyncTask中：

class CreateMovementAsyncTask extends AsyncTask<String,Void,Void>{
    protected Void doInBackground(String... arg0) {
        DBFunctions DBFunction = new DBFunctions();
        try {
            JSONObject jObjComment = new JSONObject();
            jObjComment.put("out_user", LoginActivity.name);
            jObjComment.put("out_email", arg0[1]); //use varargs instead
            jObjComment.put("out_date", arg0[2]);  //use varargs instead

            //String json = DBFunction.create_movement(GlobalClass.tablename,jObjComment.toString());
            String json = DBFunction.create_movement(arg0[0], jObjComment.toString());


            Log.d("CreateMovementAsyncTask", json);
        } catch (JSONException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        }


        return null;
    }

    protected void onPostExecute(Void json){

    }
}

使用PHP / MySql的AsyncTask无法正常工作

1 个答案: