我处于需要使用java.concurrent包中的Semaphore的情况,这样我就可以限制占用某个资源的线程数。以下是最基本的设置(代码):
package semaphor;
import java.util.concurrent.Semaphore;
/**
* Created by NawazishMohammad on 15-04-2015.
*/
public class SemaphoreTester {
public static void main (String [] args){
new Thread(new MyRunnable(), "T1").start();
new Thread(new MyRunnable(), "T2").start();
new Thread(new MyRunnable(), "T3").start();
new Thread(new MyRunnable(), "T4").start();
}
}
class MyRunnable implements Runnable{
@Override
public void run() {
semaphoreStatus();
}
public void semaphoreStatus(){
System.out.println("Thread waiting for permit: "+Thread.currentThread().getName());
Semaphore sem = new Semaphore(2);
try {
sem.acquire();
System.out.println("Thread got permit: " + Thread.currentThread().getName());
System.out.println("Thread releasing permit: "+Thread.currentThread().getName());
sem.release();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
我收到以下输出
Thread waiting for permit: T1
Thread waiting for permit: T2
Thread waiting for permit: T3
Thread waiting for permit: T4
Thread got permit: T3
Thread got permit: T4
Thread got permit: T2
Thread got permit: T1
Thread releasing permit: T2
Thread releasing permit: T4
Thread releasing permit: T3
Thread releasing permit: T1
请注意,虽然我已经实例化了Semaphore的总并发线程数为2" new Semaphore(2);
",这意味着一次只有2个线程可以访问特定资源,我可以找到全部4个线程:T1-T4已获得Semaphore许可(因此访问受限资源)。任何人都可以澄清我对java.concurrent.Semaphore
的误解,因为我不期望输出:
Thread got permit: T3
Thread got permit: T4
Thread got permit: T2
Thread got permit: T1
据我所知,信号量无论如何都不能超过" 2"允许(对于此示例)可能正在等待的任意数量的线程。
答案 0 :(得分:6)
您正在每个线程中创建一个新的信号量,这意味着每个线程将看到一个不同的信号量。你应该在线程之外构造信号量,然后与它们共享,而不是在Semaphore sem = new Semaphore(2);
内调用semaphoreStatus()
。