我试图按键对象数组进行排序,但是当对象a的键值与对象b的值相同时,将检查下一个键,直到它们最终不同为止。
我已尝试使用以下代码:
rows.sort (a, b) ->
for key, value of a
if a[key] < b[key]
return -1
else if a[key] > b[key]
return 1
else
continue
但是当初始顺序不同时,这会导致数组看起来不同。有什么想法可以实现它吗? 谢谢!
编辑之前的数组:
[ { date: "2013-02-03",
cpc: 1.46,
cost: 1.46,
clicks: 1 },
{ date: "2013-02-05",
cpc: 1.8375,
cost: 14.7,
clicks: 8 },
{ date: "2013-02-06",
cpc: 1.17,
cost: 7.02,
clicks: 6 },
{ date: "2013-02-09",
cpc: 0.23,
cost: 0.23,
clicks: 1 },
{ date: "2013-02-15",
cpc: 1.4949999999999999,
cost: 2.9899999999999998,
clicks: 2 },
{ date: "2013-02-17",
cpc: 1.21,
cost: 2.42,
clicks: 2 },
{ date: "2013-02-18",
cpc: 1.92,
cost: 9.6,
clicks: 5 },
{ date: "2013-02-02",
cpc: 1.86,
cost: 1.86,
clicks: 1 },
{ date: "2013-02-04",
cpc: 2.35,
cost: 2.35,
clicks: 1 },
{ date: "2013-02-11",
cpc: 1.9625,
cost: 7.85,
clicks: 4 },
{ date: "2013-02-16",
cpc: 2.315,
cost: 4.63,
clicks: 2 },
{ date: "2013-02-21",
cpc: 1.8566666666666667,
cost: 5.57,
clicks: 3 },
{ date: "2013-02-22",
cpc: 1.8375,
cost: 7.35,
clicks: 4 },
{ date: "2013-02-25",
cpc: 1.5066666666666668,
cost: 4.5200000000000005,
clicks: 3 },
{ date: "2013-02-26",
cpc: 2.6,
cost: 2.6,
clicks: 1 },
{ date: "2013-02-27",
cpc: 2.118,
cost: 10.59,
clicks: 5 },
{ date: "2013-02-07",
cpc: 0.2,
cost: 0.2,
clicks: 1 },
{ date: "2013-02-08",
cpc: 1.7850000000000001,
cost: 7.140000000000001,
clicks: 4 },
{ date: "2013-02-10",
cpc: 0.46,
cost: 0.46,
clicks: 1 },
{ date: "2013-02-14",
cpc: 1.955,
cost: 3.91,
clicks: 2 },
{ date: "2013-02-19",
cpc: 1.9233333333333331,
cost: 17.31,
clicks: 9 },
{ date: "2013-02-12",
cpc: 2.39,
cost: 7.17,
clicks: 3 },
{ date: "2013-02-13",
cpc: 2.53,
cost: 2.53,
clicks: 1 },
{ date: "2013-02-20",
cpc: 1.87,
cost: 1.87,
clicks: 1 },
{ date: "2013-02-23",
cpc: 2.265,
cost: 9.06,
clicks: 4 },
{ date: "2013-02-28",
cpc: 2.2425,
cost: 8.97,
clicks: 4 },
{ date: "2013-03-01",
cpc: 1.83,
cost: 3.66,
clicks: 2 } ]
排序后的结果(这是我期待的结果):
[ { date: '2013-02-02',
cpc: 1.86,
cost: 1.86,
clicks: 1 },
{ date: '2013-02-03',
cpc: 1.46,
cost: 1.46,
clicks: 1 },
{ date: '2013-02-04',
cpc: 2.35,
cost: 2.35,
clicks: 1 },
{ date: '2013-02-05',
cpc: 1.8375,
cost: 14.7,
clicks: 8 },
{ date: '2013-02-06',
cpc: 1.17,
cost: 7.02,
clicks: 6 },
{ date: '2013-02-07',
cpc: 0.2,
cost: 0.2,
clicks: 1 },
{ date: '2013-02-08',
cpc: 1.7850000000000001,
cost: 7.140000000000001,
clicks: 4 },
{ date: '2013-02-09',
cpc: 0.23,
cost: 0.23,
clicks: 1 },
{ date: '2013-02-10',
cpc: 0.46,
cost: 0.46,
clicks: 1 },
{ date: '2013-02-11',
cpc: 1.9625,
cost: 7.85,
clicks: 4 },
{ date: '2013-02-12',
cpc: 2.39,
cost: 7.17,
clicks: 3 },
{ date: '2013-02-13',
cpc: 2.53,
cost: 2.53,
clicks: 1 },
{ date: '2013-02-14',
cpc: 1.955,
cost: 3.91,
clicks: 2 },
{ date: '2013-02-15',
cpc: 1.4949999999999999,
cost: 2.9899999999999998,
clicks: 2 },
{ date: '2013-02-16',
cpc: 2.315,
cost: 4.63,
clicks: 2 },
{ date: '2013-02-17',
cpc: 1.21,
cost: 2.42,
clicks: 2 },
{ date: '2013-02-18',
cpc: 1.92,
cost: 9.6,
clicks: 5 },
{ date: '2013-02-19',
cpc: 1.9233333333333331,
cost: 17.31,
clicks: 9 },
{ date: '2013-02-20',
cpc: 1.87,
cost: 1.87,
clicks: 1 },
{ date: '2013-02-21',
cpc: 1.8566666666666667,
cost: 5.57,
clicks: 3 },
{ date: '2013-02-22',
cpc: 1.8375,
cost: 7.35,
clicks: 4 },
{ date: '2013-02-23',
cpc: 2.265,
cost: 9.06,
clicks: 4 },
{ date: '2013-02-25',
cpc: 1.5066666666666668,
cost: 4.5200000000000005,
clicks: 3 },
{ date: '2013-02-26',
cpc: 2.6,
cost: 2.6,
clicks: 1 },
{ date: '2013-02-27',
cpc: 2.118,
cost: 10.59,
clicks: 5 },
{ date: '2013-02-28',
cpc: 2.2425,
cost: 8.97,
clicks: 4 },
{ date: '2013-03-01',
cpc: 1.83,
cost: 3.66,
clicks: 2 } ]
当你的订单被打扰时,初始数组:
[ { date: '2013-02-02',
cpc: 1.86,
cost: 1.86,
clicks: 1 },
{ date: '2013-02-04',
cpc: 2.35,
cost: 2.35,
clicks: 1 },
{ date: '2013-02-05',
cpc: 1.8375,
cost: 14.7,
clicks: 8 },
{ date: '2013-02-06',
cpc: 1.17,
cost: 7.02,
clicks: 6 },
{ date: '2013-02-11',
cpc: 1.9625,
cost: 7.85,
clicks: 4 },
{ date: '2013-02-12',
cpc: 2.39,
cost: 7.17,
clicks: 3 },
{ date: '2013-02-16',
cpc: 2.315,
cost: 4.63,
clicks: 2 },
{ date: '2013-02-18',
cpc: 1.92,
cost: 9.6,
clicks: 5 },
{ date: '2013-02-20',
cpc: 1.87,
cost: 1.87,
clicks: 1 },
{ date: '2013-02-21',
cpc: 1.8566666666666667,
cost: 5.57,
clicks: 3 },
{ date: '2013-02-28',
cpc: 2.2425,
cost: 8.97,
clicks: 4 },
{ date: '2013-03-01',
cpc: 1.83,
cost: 3.66,
clicks: 2 },
{ date: '2013-02-03',
cpc: 1.46,
cost: 1.46,
clicks: 1 },
{ date: '2013-02-07',
cpc: 0.2,
cost: 0.2,
clicks: 1 },
{ date: '2013-02-09',
cpc: 0.23,
cost: 0.23,
clicks: 1 },
{ date: '2013-02-10',
cpc: 0.46,
cost: 0.46,
clicks: 1 },
{ date: '2013-02-17',
cpc: 1.21,
cost: 2.42,
clicks: 2 },
{ date: '2013-02-19',
cpc: 1.9233333333333331,
cost: 17.31,
clicks: 9 },
{ date: '2013-02-25',
cpc: 1.5066666666666668,
cost: 4.5200000000000005,
clicks: 3 },
{ date: '2013-02-08',
cpc: 1.7850000000000001,
cost: 7.140000000000001,
clicks: 4 },
{ date: '2013-02-13',
cpc: 2.53,
cost: 2.53,
clicks: 1 },
{ date: '2013-02-14',
cpc: 1.955,
cost: 3.91,
clicks: 2 },
{ date: '2013-02-15',
cpc: 1.4949999999999999,
cost: 2.9899999999999998,
clicks: 2 },
{ date: '2013-02-22',
cpc: 1.8375,
cost: 7.35,
clicks: 4 },
{ date: '2013-02-23',
cpc: 2.265,
cost: 9.06,
clicks: 4 },
{ date: '2013-02-26',
cpc: 2.6,
cost: 2.6,
clicks: 1 },
{ date: '2013-02-27',
cpc: 2.118,
cost: 10.59,
clicks: 5 }]
使用hussled array进行排序的结果:
[ { date: '2013-02-02',
cpc: 1.86,
cost: 1.86,
clicks: 1 },
{ date: '2013-02-03',
cpc: 1.46,
cost: 1.46,
clicks: 1 },
{ date: '2013-02-04',
cpc: 2.35,
cost: 2.35,
clicks: 1 },
{ date: '2013-02-05',
cpc: 1.8375,
cost: 14.7,
clicks: 8 },
{ date: '2013-02-06',
cpc: 1.17,
cost: 7.02,
clicks: 6 },
{ date: '2013-02-07',
cpc: 0.2,
cost: 0.2,
clicks: 1 },
{ date: '2013-02-08',
cpc: 1.7850000000000001,
cost: 7.140000000000001,
clicks: 4 },
{ date: '2013-02-10',
cpc: 0.46,
cost: 0.46,
clicks: 1 },
{ date: '2013-02-11',
cpc: 1.9625,
cost: 7.85,
clicks: 4 },
{ date: '2013-02-12',
cpc: 2.39,
cost: 7.17,
clicks: 3 },
{ date: '2013-02-13',
cpc: 2.53,
cost: 2.53,
clicks: 1 },
{ date: '2013-02-14',
cpc: 1.955,
cost: 3.91,
clicks: 2 },
{ date: '2013-02-15',
cpc: 1.4949999999999999,
cost: 2.9899999999999998,
clicks: 2 },
{ date: '2013-02-16',
cpc: 2.315,
cost: 4.63,
clicks: 2 },
{ date: '2013-02-17',
cpc: 1.21,
cost: 2.42,
clicks: 2 },
{ date: '2013-02-18',
cpc: 1.92,
cost: 9.6,
clicks: 5 },
{ date: '2013-02-19',
cpc: 1.9233333333333331,
cost: 17.31,
clicks: 9 },
{ date: '2013-02-20',
cpc: 1.87,
cost: 1.87,
clicks: 1 },
{ date: '2013-02-21',
cpc: 1.8566666666666667,
cost: 5.57,
clicks: 3 },
{ date: '2013-02-22',
cpc: 1.8375,
cost: 7.35,
clicks: 4 },
{ date: '2013-02-23',
cpc: 2.265,
cost: 9.06,
clicks: 4 },
{ date: '2013-02-09',
cpc: 0.23,
cost: 0.23,
clicks: 1 },
{ date: '2013-02-25',
cpc: 1.5066666666666668,
cost: 4.5200000000000005,
clicks: 3 },
{ date: '2013-02-26',
cpc: 2.6,
cost: 2.6,
clicks: 1 },
{ date: '2013-02-27',
cpc: 2.118,
cost: 10.59,
clicks: 5 },
{ date: '2013-02-28',
cpc: 2.2425,
cost: 8.97,
clicks: 4 },
{ date: '2013-03-01',
cpc: 1.83,
cost: 3.66,
clicks: 2 } ]
答案 0 :(得分:3)
您不需要continue
。并确保在对象匹配时返回0
:
rows.sort (a, b) ->
for key, value of a
if a[key] < b[key]
return -1
else if a[key] > b[key]
return 1
return 0
更大的问题 - 对象键没有排序。没有理由期望,每次通过for循环,第一个键将是日期,第二个键将是cpc等。你真的想要按顺序拥有预定义的键数组,并使用而不只是从对象中获取键列表
keys = ["a","b","c"]
rows.sort (a, b) ->
for key in keys
if a[key] < b[key]
return -1
else if a[key] > b[key]
return 1
return 0
答案 1 :(得分:0)
我正要问这个问题,但发现有一个类似的问题,原来答案是我已经在做的事,但这有一个FOR IN循环。 我测试了一下,没有给我想要的东西 然后,我决定在值相同时换出for in循环以获取更多代码。 这是结果