Question

我正在尝试从查询字符串中获取值并将它们添加到数组内的数组中。输出查询字符串类似于：

add_to_cart.php?product_id=4&product_name=Pizza&quantity=1&additional_id[]=1&additional_quantity[]=3&additional_id[]=4&additional_quantity[]=5

我在查询字符串中显示每个additional_id和additional_quantity变量，并带有以下代码。我将每个additional_id与我在数据库表附加中的ID进行比较，并将all插入到数组中。我的文件 add_to_cart.php 文件中存在以下代码：

if(isset($_SESSION['cart']))
{
    while ($row = $stmt->fetch(PDO::FETCH_ASSOC))
    {
        extract($row);
        $columns = array
        (
            'product_id_session' => $product_id_session,
            'product_id' => $product_id,
            'product_name' => $product_name,
            'product_price' => $product_price,
            'quantity' => $quantity,
            'additionals' => array()                        
        );
        if(isset($_GET['additional_id']) && $_GET['additional_id'] != "")
        {
            foreach($_GET['additional_id'] as $additional => $value)
            {
                $additional_id = $value;
                if(isset($_GET['additional_quantity'][$additional]))
                {
                    $additional_quantity = $_GET['additional_quantity'][$additional];
                    if($additional_quantity <= 0 || $additional_quantity > 5)
                    {
                        $additional_quantity = null;
                    }
                    else
                    {
                        $sql2 = "SELECT additional_id, additional_name, additional_price FROM additionals WHERE additional_id LIKE '{$additional_id}'";
                        $stmt2 = $connection->prepare($sql2);
                        $stmt2->execute();
                        while ($row = $stmt2->fetch(PDO::FETCH_ASSOC))
                        {
                            extract($row);
                            $columns['additionals'][]['additional_id'] = $additional_id;
                            $columns['additionals'][]['additional_name'] = $additional_name;
                            $columns['additionals'][]['additional_price'] = $additional_price;
                            $columns['additionals'][]['additional_quantity'] = $additional_quantity;
                        }
                    }
                }
            }
        }
        $_SESSION['cart'][$product_id_session] = $columns;
    }
    header('Location: products.php?action=added&product_name=' . $product_name);
}

在cart会话中添加所有内容后，在 cart.php 页面中，我正在尝试使用所选的附加内容和数量来展示产品：

foreach($_SESSION['cart'] as $product)
{
    echo "<tr>";
        echo "<td>{$product['product_name']}</td>";
        echo "<td>&#36;{$product['product_price']}</td>";
        echo "<td>{$product['quantity']}</td>";
        echo "<td>";
        foreach($product['additionals'] as $additional)
        {
            echo "<p>{$additional['additional_quantity']}x{$additional['additional_name']} - {$additional['additional_price']}</p>";
        }
        echo "</td>";
    echo "</tr>";
}

但是我做错了，我认为这两个代码不能正常工作我的输出很尴尬，就像这样：
enter image description here

我是以正确的方式做到的吗？也许我没有使用foreach正确循环，或者附加功能没有成功添加？对不起，我以前从未使用过多维数组。有办法做我想做的事吗？谢谢！

Answer 1

根据评论的解决方案 -
您的问题是由$columns['additionals'][]引起的，因为它导致每个值都被添加为自己的数组。这是通过添加$additional作为数组键 -

来解决的

while ($row = $stmt2->fetch(PDO::FETCH_ASSOC))
{
    extract($row);
    $columns['additionals'][$additional]['additional_id'] = $additional_id;
    $columns['additionals'][$additional]['additional_name'] = $additional_name;
    $columns['additionals'][$additional]['additional_price'] = $additional_price;
    $columns['additionals'][$additional]['additional_quantity'] = $additional_quantity;
}

或者你也可以 -

while ($row = $stmt2->fetch(PDO::FETCH_ASSOC))
{
    extract($row);
    $columns['additionals'][] = array('additional_id' => $additional_id,
                                      'additional_name' => $additional_name,
                                      'additional_price' => $additional_price,
                                      'additional_quantity' => $additional_quantity);
}

多维数组中存在的数据无法正确显示

1 个答案: