在mysql#1064中存储函数创建错误

时间:2015-04-15 14:21:00

标签: mysql stored-procedures

我尝试创建一个函数,即如果用户名存在,则会将随机数和字符作为单个字符串返回,但我尝试了下面的代码,抛出如下的语法错误,你能帮助找到问题,我知道有声明字符串和返回字符串的问题,但无法找到问题。感谢提前回复

DELIMITER //
create function verifyEmail(userName varchar(25))
RETURNS TEXT
BEGIN
    if EXISTS(select * from userdetails where name = userName)
    then
        SELECT @randomPass := select concat( char(round(rand()*36)+1), char(round(rand()*36)+1), char(round(rand()*36)+1));
        return @randomPass;
    else
       return "not_exist";
    end if;
 end //
DELIMITER //

#1064 - 您的SQL语法出错;检查与MySQL服务器版本对应的手册,以便在'select concat(char(round(rand()* 36)+1)附近使用正确的语法,char(round(rand()* 36)+1),char (圆形(ra'在第6行

2 个答案:

答案 0 :(得分:0)

您错过了此行的结束)

SELECT @randomPass := select concat( char(round(rand()*36)+1), char(round(rand()*36)+1), char(round(rand()*36)+1);

应该是

SELECT @randomPass := select concat( char(round(rand()*36)+1), char(round(rand()*36)+1), char(round(rand()*36)+1));

答案 1 :(得分:0)

万岁,终于找到答案..这下面的代码将有助于解决问题

DELIMITER //
create function verifyEmail(userName varchar(25))
RETURNS TEXT
BEGIN
    DECLARE randomPass VARCHAR(8);
    if EXISTS(select id from userdetails where name = userName)
    THEN        
       SET randomPass = concat( char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65));
       return randomPass;
    else
       return "not_exist";
    end if;
 end //
DELIMITER //