Question

我正在尝试使用方法找到前100个五角形数字。下面是我的代码，但是，我一直在错过return语句。我确定我没有适当地提交退货声明，除非我不知道这个过程是否正确。因此，我很感激指导。谢谢。 PS：尚未学习阵列，这不是作业

public class PentagonNumber {
    public static void main(String[] args) {
        int numberperline = 10;
        int n = 1;
        int count = 0;
        int pent = getpentagonnumber(n);
        count++;

        if (count % numberperline == 0)
            System.out.println();
        else System.out.print(pent + "\t");
    }

    public static int getpentagonnumber(int x) {
        for (int count = 0; count < 100; count++) {
            for (x = 1; x <= 100; x++) {
                int result;
                result = x * (3 * x - 1) / 2;
                return result;
            }
        }
    }
}

Answer 1

您的代码应该像这样更改：

public class PentagonNumber {
    public static void main(String[] args) {
        int numberperline = 10;
        //int n = 1; // you do not need N
        //int count = 0; // you do not this either
        for (x = 0; x < 100; x++) { // moved
            int pent = getpentagonnumber(x+1); // +1 so it goes 1::100
            //count++;
            if (x % numberperline == 0)
                System.out.println();
            //else // you were skipping every tenth result.
            System.out.print(pent + "\t");
        }// close for
    }

    public static int getpentagonnumber(int x) {
        //for (int count = 0; count < 100; count++) { // moved
            //for (x = 1; x <= 100; x++) { // removed
                int result; // no need to declare and then calculate
                result = x * (3 * x - 1) / 2; // but not wrong either.
                return result;
            //}
        //}
    }
}

Answer 2

在for循环中只有一个返回值。你可能意味着：

public  static  int getpentagonnumber(int x ){
   int  result = 0;
   for (int count=0; count<100; count++){
        for (x=1;x<=100;x++){         
            result = x*(3*x-1)/2;
        }
   } //this was missing
   return result; 
}

缺少return语句（Java）：计算前100个五角形数字）

2 个答案: