Question

我正在使用Access 2010，并且我继承了一个包含培训主题的表。其中一些科目是主要科目，一些科目是主要科目的子科目（均在同一张表中）。主表按编号索引：

ID  |   Type    |   Department  |   Subject                         |   Sub 1   |   Sub 2   |   Sub 3
----+-----------+---------------+-----------------------------------+-----------+-----------+-----------
1   |   Main    |   Candy       |   Chocolate covered bananas       |   2       |   3       |   4
2   |   Sub     |   Candy       |   Melting Chocolate               |           |           |
3   |   Sub     |   Candy       |   Dipping machine                 |           |           |
4   |   Sub     |   Candy       |   Freezer Operation               |           |           |
5   |   Main    |   Candy       |   Chocolate covered Strawberries  |   2       |   3       |

我试图制作一份报告，显示主要主题，然后是主要主题的子要求。所以报告看起来像这样：

糖果部门

涂有巧克力的香蕉
- 融化巧克力
- 浸渍机
- 冷冻机操作
巧克力草莓
- 融化巧克力
- 浸渍机

等...

我无法弄清楚如何使关系或查找命令正确以获得正确的引用。我开始怀疑我必须把表分成两个 - 一个用于主要科目，一个用于子要求。但这并不是一个很好的选择，因为它有点大表并且与其他报表和查询相关联。其中一些主题包含多达10个子区域（表格中的字段多于我在此处指出的字段，但其中很多字段对于解决方案来说并不是必需的）

Answer 1

这可以通过写一个＆＃34; Union＆＃34;查询。

选择＆＃34; SQL＆＃34; Access中的查看模式可以使用此类查询。

这里的目标是＆＃34; unpivot＆＃34;数据，以便每个子类型都有一个返回主类型的引用。

SELECT  Table1.ID AS MainID
      , Table1.Department AS MainDepartment
      , Table1.Subject AS MainSubject
      , Table1_1.ID AS SubID
      , Table1_1.Department AS SubDepartment
      , Table1_1.Subject AS SubSubject
FROM    Table1
        INNER JOIN Table1 AS Table1_1 ON Table1.[Sub 1] = Table1_1.ID
UNION
SELECT  Table1.ID AS MainID
      , Table1.Department AS MainDepartment
      , Table1.Subject AS MainSubject
      , Table1_1.ID AS SubID
      , Table1_1.Department AS SubDepartment
      , Table1_1.Subject AS SubSubject
FROM    Table1
        INNER JOIN Table1 AS Table1_1 ON Table1.[Sub 2] = Table1_1.ID
UNION
SELECT  Table1.ID AS MainID
      , Table1.Department AS MainDepartment
      , Table1.Subject AS MainSubject
      , Table1_1.ID AS SubID
      , Table1_1.Department AS SubDepartment
      , Table1_1.Subject AS SubSubject
FROM    Table1
        INNER JOIN Table1 AS Table1_1 ON Table1.[Sub 3] = Table1_1.ID;

每个子类型的输出应该有1行。 Union query results

表/报告中的子引用生成以显示访问中的子引用

1 个答案: