Question

我正在尝试使用SQL Server 2008的FOR XML PATH功能。但我没有得到我预期的输出。

我有一张这样的表：

     EventId EventDesc WeekName
     --------------------------------
     101      A          sunday
     102      B          Monday
     103      C          wednesaday

如何像这样输出XML：

<Events>
  <sunday>
     <E>
        <NE>
           <EventId>101</EventID>
           <Name>A</Name>
        </NE>
     </E>
   </sunday>
   <Monday>
      <E>
         <NE>
            <EventId>102</EventID>
            <Name>B</Name>
         </NE>
      </E>
   </Monday>
   <Tuesday>
      <E>
         <NE>
            <EventId>103</EventID>
            <Name>C</Name>
         </NE>
      </E>
   </Tuesday>
</Events>

我使用的查询：

select  
    (select 
        [EventID] as ID, 
        [EventDesc] as D
     from 
        TempEvent 
     where 
        WeekName = 'sunday' 
     FOR XML PATH('NE'), Root('E'), type)    
FOR XML PATH ('sunday')

我的问题是，如何获取XML输出中每行的工作名？

Answer 1

它不是最好的解决方案（绝对不优雅），因为它使用字符串连接来构建XML，但它可以完成工作。

;WITH CTE as 
(
    SELECT 101 as EventId,      'A' as EventDesc,          'sunday' as WeekName
    UNION ALL SELECT      102 as EventId,      'B' as EventDesc,          'Monday'
    UNION ALL SELECT      103 as EventId,      'C' as EventDesc,          'wednesaday'
)
SELECT '<Events>' +(
SELECT DISTINCT '<' + WeekName +'>' + (SELECT EventId,EventDesc FROM CTE  C2 WHERE C2.WeekName = C1.WeekName FOR XML PATH('NE'),ROOT('E')) + '</' + WeekName +'>'
FROM CTE C1
FOR XML PATH('Events'),TYPE).value('.','NVARCHAR(MAX)') + '</Events>'

SQL Server XML Path在根元素上添加weekname

1 个答案: