在sql server中选择2个不同的计数

时间:2015-04-15 07:46:08

标签: sql sql-server sql-server-2008 count sql-server-2012

我需要从我的表中选择前20000,它有几列(数字,颜色等...),我需要在一个查询中从这些20000中得到红色的计数和蓝色的计数。

我知道如果我在临时表中插入前20000然后从临时表中选择红色计数然后从临时表中选择蓝色计数,我就能得到我想要的东西,但我需要这样做在一个查询中。

我尝试了以下但它给了我每个数字的计数,我需要总数..

SELECT  top 20000 [number], count(color)
FROM [profile]
group by number
having color='red'

输出:

颜色|计数

红色| 15000

蓝色| 5000

3 个答案:

答案 0 :(得分:2)

您可以使用iif

select  top 20000 [number]
     , sum(iif([color] = 'red', 1, 0) as red_count
     , sum(iif([color] = 'blue', 1, 0) as blue_count
from [profile]
group by [number]

case

select  top 20000 [number]
     , sum(case when [color] = 'red' then 1 else 0 end) as red_count
     , sum(case when [color] = 'blue' then 1 else 0 end) as blue_count
from [profile]
group by [number]

修改即可。在您更新了问题后,我猜您的查询应如下所示:

select t.[color]
     , count(t.[color])
from (select  top 20000 [color] from [profile]) t
group by t.[color]

答案 1 :(得分:1)

您可以使用嵌套查询:

select inner.color, count(*) from 
(select top 20000 [number], color from [profile]) inner
group by inner.color

答案 2 :(得分:0)

SELECT  top 20000 [number], count(color) as count_total, 
        sum(case when color='red' then 1 else 0 end) as count_red, 
        sum(case when color='blue' then 1 else 0 end) as count_blue
FROM [profile]
group by number