Question

之前我做了这个帖子，但我确实得到了很多预期的帮助。让我借此机会尽量保持清醒。 1.我有这个谷歌表ID 1UJVQGlCpsxtqN-IkRFFgHEnzNaq-HQDaiw-hte5j3LY

Email Address   Name   Mark1    Mark2    Mark3  Remark  Email Sent
abc@gmail.com   John    34      21       34     Fair    
def@gmail.com   Sam     23      9        78     fair

Tamplate Doc。 ID 15SP7mxyKYF6ptuRfrudNsvtJuezMTOBUL_cRCFbBIcI

亲爱的keyName

标记1 MARK2 MARK3 keyMark_1 keyMark_2 keyMark_3

备注 keyRemark

代码。

//在G列中写入电子邮件的行的Email_Sent //已成功发送。 var EMAIL_SENT =＆＃34; EMAIL_SENT＆＃34 ;;

function sendEmails2() {
  var sheet = SpreadsheetApp.getActiveSheet();
  var startRow = 2;  // First row of data to process
  var numRows = 5;   // Number of rows to process
  var dataRange = sheet.getRange(startRow, 1, numRows, 6)
  var ss = SpreadsheetApp.openById('1UJVQGlCpsxtqN-IkRFFgHEnzNaq-HQDaiw-hte5j3LY'); 
  var sheet = ss.getSheetByName('Email Spreadsheet Data');
  //var dataRange = sheet.getRange(2, 1, sheet.getLastRow(), sheet.getLastColumn());
  var copyId = DocsList.getFileById('15SP7mxyKYF6ptuRfrudNsvtJuezMTOBUL_cRCFbBIcI')
    .makeCopy(name)
    .getId();

  // Fetch values for each row in the Range.
  var data = dataRange.getValues();
  for (var i = 0; i < data.length; ++i){
  //for (var j = 0; j < startRow; ++j) {
    var row = data[i];
    var emailAddress = row[0];  // First column
    var name = row[1]; // Second column
    var Mark1 = row[2]; // Third column
    var Mark2 = row[3]; // Fourth column
    var Mark3 = row[4]; // 
    var remark = row[5]; // 
    var emailSent = row[6]; // 
    var static_copy = ('goins@mu.ac.ke');

    // Open the temporary document
  var copyDoc = DocumentApp.openById(copyId);
  // Get the document’s body section
  var copyBody = copyDoc.getActiveSection();

// Replace place holder keys,in google doc template. Create a blank document with the number "1,2,3....", and it will replace this text with value
  copyBody.replaceText('keyName', name)
  copyBody.replaceText('keyMark_1', Mark1)
  copyBody.replaceText('keyMark_2', Mark2)
  copyBody.replaceText('keyMark_3', Mark3)
  copyBody.replaceText('keyRemark', remark)

// Save and close the temporary document
  copyDoc.saveAndClose();

// Convert temporary document to PDF
  var pdf = DocsList.getFileById(copyId).getAs("application/pdf");

// Attach PDF and send the email
  var subject = "Profile";
  var body = "<HTML><BODY>"
             + "Dear "+ name +",<br>"
             + "<br>"
             + " Regards <br>"
             + "<br>"
             + "</HTML></BODY>";

  MailApp.sendEmail(emailAddress, subject, body, 
                   {htmlBody: body, attachments: pdf, cc: static_copy,});
 //if (emailSent != EMAIL_SENT) {  // Prevents sending duplicates
      //var subject = "Sending emails from a Spreadsheet";
     // MailApp.sendEmail(emailAddress, subject, {htmlBody: body, attachments: pdf, cc: static_copy,});
    //sheet.getRange(startRow + i, 6).setValue(EMAIL_SENT);
   // Delete temp file
  DocsList.getFileById(copyId).setTrashed(true);  
      } // Make sure the cell is updated right away in case the script is interrupted
     SpreadsheetApp.flush();
    }

当我执行上述脚本时，带有John标记的电子邮件附件将发送到adc@gmail.com和efg@gmail.com。我需要你的帮助才能解决这个问题，这样我就可以给每个学生发送一封带有结果的电子邮件附件。

请帮助

塞米。

Answer 1

copyId变量应该在for循环中声明;声明copyId时，变量name未定义。

此外，您正在使用一些已弃用的API（例如DocsList）。

Google表格 - 发送电子邮件

1 个答案: