Question

HTML

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Murach's Java Servlets and JSP</title>
</head>

<body>
    <%-- import packages and classes needed by the scripts --%>
    <%@ page import="business.*, data.*" %>

    <%
        //get parameters from the request
        String firstName = request.getParameter("firstName");
        String lastName = request.getParameter("lastName");
        String emailAddress = request.getParameter("emailAddress");

        // get the real path for the EmailList.txt file
        ServletContext sc = this.getServletContext();
        String path = sc.getRealPath("/WEB-INF/EmailList.txt");

        // use regular Java objects
        User user = new User(firstName, lastName, emailAddress);
        UserIO.add(user, path);
    %>
    <h1>Thanks for joining our email list</h1>
    <p>Here is the information that you entered: </p>
    <table cellspacing="5" cellpadding="5" border="1">
        <tr>
            <td align="right">First name:</td>
            <td><%= firstName %></td>
        </tr>
        <tr>
            <td align="right">Last name:</td>
            <td><%= lastName %></td>
        </tr>
        <tr>
            <td align="right">Email Address:</td>
            <td><%= emailAddress %></td>
        </tr>
    </table>

    <p>To enter another email address, click on the Back <br />
    button in your browser or the Return button shown <br />
    below.</p>

    <form action="index.jsp" method="post">
        <input type="submit" value="Return" />
    </form>

</body>
</html>

它给了我这个错误页面......

编译'C：\ bea \ user_projects \ domains \ mydomain。\ myserver.wlnotdelete \ extract \ myserver_sample01_WebContent \ jsp_servlet__display_email_entry.java'
失败了：   C：\ BEA \ user_projects \域\ MYDOMAIN \ myserver.wlnotdelete \提取\ myserver_sample01_WebContent \ jsp_servlet__display_email_entry.java：140：   可能无法解析符号   由于错误而发生   /display_email_entry.jsp第19行：
  ServletContext sc =   this.getServletContext（）;

完整编译器错误： C：\ bea \ user_projects \ domains \ mydomain。\ myserver.wlnotdelete \ extract \ myserver_sample01_WebContent \ jsp_servlet__display_email_entry.java:140：   无法解析符号
符号：方法   getServletContext（）
location：class   为jsp_servlet .__ display_email_entry
  ServletContext sc = this.getServletContext（）; // [   /display_email_entry.jsp;行：19] ^

1错误
星期四03月15日15:56:09 CST 2010

任何提示？我是JSP新手，这是我的第一次学习练习...... google.com无法找到它....

谢谢！

Answer 1

对于getServletContext

，Weblogic中的JSP与Tomcat的行为不同

替换ServletContext sc = this.getServletContext();

到ServletContext sc = getServletConfig().getServletContext();

jsp getServletContext（）错误

1 个答案: