Question

Python 3.我试图返回该函数，以便它只需一个单词并将其转换为Cow Latin。我想在运行我的功能时摆脱方括号，逗号和单撇号。

我的功能是：

alpha = list("bcdfghjklmnpqrstvwxyz")
def cow_latinify_word(word):
    if word[0].lower() in alpha:
        lista = (word.lower())
        return lista[1:] + lista[0] + "oo"
    else:
        return word + "moo"

def cow_latinify_sentence(sentence):
    words = sentence.split();
    return [cow_latinify_word(word) for word in words]

当我用

测试功能时

cow_latin = cow_latinify_sentence("Cook me some eggs")
print(cow_latin)

我得到['ookcoo', 'emoo', 'omesoo', 'eggsmoo']，但我想要ookcoo emoo omesoo eggsmoo

Answer 1

使用' '.join(list)将列表元素连接成一个字符串。

在您的代码中：

alpha = list("bcdfghjklmnpqrstvwxyz")
def cow_latinify_word(word):
    if word[0].lower() in alpha:
        lista = (word.lower())
        return lista[1:] + lista[0] + "oo"
    else:
        return word + "moo"

def cow_latinify_sentence(sentence):
    words = sentence.split();
    return ' '.join([cow_latinify_word(word) for word in words])

Answer 2

您的函数cow_latinify_sentence会返回join所需的字符串列表，其中包含空格以获得所需的输出：

print(" ".join(cow_latin))

Answer 3

只需在变量名称前添加一个星号，即可解压缩列表并将其元素作为位置参数提供给print。

print(*cow_latin)

Answer 4

让我们定义变量：

>>> consonants = "bcdfghjklmnpqrstvwxyz"
>>> sentence = "Cook me some eggs"

找到牛拉丁语：

>>> ' '.join(word[1:] + word[0] + 'oo' if word[0] in consonants else word + 'moo' for word in sentence.lower().split())
'ookcoo emoo omesoo eggsmoo'

删除方括号，逗号和单引号？

4 个答案: