我正在为以下场景撰写elasticsearch
查询:
- field1 field2
- 2015 20
- 2015 14
- 2014 39
- 2013 76
- 2013 2
- 2013 55
我希望为每个唯一field2
找到field1
的总和,field2
是field1
的最大值。
例如。在这种情况下,我想要value = 20 + 39 + 76
。
返回此值的elasticsearch
查询是什么?
答案 0 :(得分:0)
我不认为弹性搜索1.x可以使用单个查询。 在2.0中,我们可能会有reducers这样的功能(参见:https://github.com/elastic/elasticsearch/issues/8110)。
您可以获得任务的第一部分(field2的最大值按字段1分组),如下所示:
DELETE /test_index
PUT /test_index
{
"settings": {
"number_of_shards": 1
}
}
POST /test_index/_bulk
{"index":{"_index":"test_index","_type":"doc","_id":1}}
{"field1":2015,"field2":20}
{"index":{"_index":"test_index","_type":"doc","_id":2}}
{"field1":2015,"field2":14}
{"index":{"_index":"test_index","_type":"doc","_id":3}}
{"field1":2014,"field2":39}
{"index":{"_index":"test_index","_type":"doc","_id":4}}
{"field1":2013,"field2":76}
{"index":{"_index":"test_index","_type":"doc","_id":5}}
{"field1":2013,"field2":2}
{"index":{"_index":"test_index","_type":"doc","_id":6}}
{"field1":2013,"field2":55}
POST /test_index/_search
{
"size": 0,
"aggs": {
"field1_group": {
"terms": {
"field": "field1",
"size": 0,
"order": {
"maksior": "asc"
}
},
"aggs": {
"maksior": {
"max": {
"field": "field2"
}
}
}
}
}
}
会给你:
{
"took": 1,
"timed_out": false,
"_shards": {
"total": 1,
"successful": 1,
"failed": 0
},
"hits": {
"total": 6,
"max_score": 0,
"hits": []
},
"aggregations": {
"field1_group": {
"doc_count_error_upper_bound": 0,
"sum_other_doc_count": 0,
"buckets": [
{
"key": 2015,
"doc_count": 2,
"maksior": {
"value": 20
}
},
{
"key": 2014,
"doc_count": 1,
"maksior": {
"value": 39
}
},
{
"key": 2013,
"doc_count": 3,
"maksior": {
"value": 76
}
}
]
}
}
}
然后你可以迭代结果并在客户端汇总它们。