以迭代方式在文件名中打印SQL输出

Question

我试图从数据库中提取数据存储每个记录在自己的文本文件中。为了正确命名文本文件，我想将文件名写为存储在数据库中的记录的ID。我如何调整以下代码来做到这一点？

    cur.execute("select postid, flatcontent from openscattachments where hasattachment is not null order by postid;")
    for i, row in enumerate(cur):
        with open('{}.txt'.format(i), 'w') as f:
        f.write('{}'.format(row))

Answer 1

您可以直接解压由cur返回的元组，而不是使用enumerate。

sql = "select postid, flatcontent from openscattachments where hasattachment is not null order by postid;"
cur.execute(sql)

for (postid, flatcontent) in cur:
    with open('{}.txt'.format(postid), 'w') as f:
    f.write('{}'.format(row))