如何在SQL（Oracle）中加入两个查询

Question

我如何加入这些查询？

SELECT RCTDT, SUM(RCTAMOUNT), COUNT(RCTAMOUNT) FROM RECEIPTS4
WHERE RCTDT BETWEEN '01-nov-2009' AND '30-nov-2009' 
AND RCTTYPE='CA' AND RCTAMOUNT>0
GROUP BY RCTDT

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SELECT RCTDT, SUM(RCTAMOUNT), COUNT(RCTAMOUNT) FROM RECEIPTS4
WHERE RCTDT BETWEEN '01-nov-2009' AND '30-nov-2009' 
AND RCTTYPE='CQ' AND RCTAMOUNT>0
GROUP BY RCTDT

Answer 1

使用IN运算符：

SELECT RCTDT, SUM(RCTAMOUNT), COUNT(RCTAMOUNT) FROM RECEIPTS4
WHERE RCTDT BETWEEN '01-nov-2009' AND '30-nov-2009' 
AND RCTTYPE IN ('CA','CQ') AND RCTAMOUNT>0
GROUP BY RCTDT

Answer 2

也许你的意思是

SELECT RCTDT,
 SUM(case when rcttype='CA' then RCTAMOUNT else null end) as CASUM, 
 COUNT(case when rcttype='CA' then RCTAMOUNT else null end) as CACOUNT,
 SUM(case when rcttype='CQ' then RCTAMOUNT else null end) as CQSUM, 
 COUNT(case when rcttype='CQ' then RCTAMOUNT else null end) as CQCOUNT,
FROM RECEIPTS4
WHERE RCTDT BETWEEN '01-nov-2009' AND '30-nov-2009' 
AND RCTTYPE in('CA','CQ') AND RCTAMOUNT>0
GROUP BY RCTDT

Answer 3

在此特定示例中，使用cletus建议的IN。在其他情况下，如果无法从同一个选择中生成两个结果集，请使用UNION来组合结果：

SELECT something FROM somewhere
UNION
SELECT something FROM somewhere_else

Answer 4

来自RECEIPTS4的SELECT RCTDT，SUM（RCTAMOUNT），COUNT（RCTAMOUNT） '01 -nov-2009'和'30 -nov-2009'之间的关系 AND RCTTYPE IN（'CA'，'CQ'）和RCTAMOUNT＆gt; 0 GROUP BY RCTDT

也很有用。