Question

我需要打印到一个写入的两个IMG标签但是使用不同的ID只使用一个行回送代码？

示例：

$sql = mysql_query("SELECT * FROM products ORDER BY pid");

while ($data = mysql_fetch_array($sql)){
 echo "<div class=\"item\">\n";
 echo "<div>";
 echo "<img src=\"img/products/".$data['photo']."\" />";
 echo "</div>";
 echo "</div>\n";
}

输出：

<div class="item">
<div>
<img src="img/products/1.png" />
<img src="img/products/2.png" />
</div>
</div>

Answer 1

你只需要在循环外移动外部html。这样，在每行打印图像标签时仅打印一次。例如：

$sql = mysql_query("SELECT * FROM products ORDER BY pid");
echo "<div class=\"item\">\n";
echo "<div>";
while ($data = mysql_fetch_array($sql)){
 echo "<img src=\"img/products/".$data['photo']."\" />";
}
echo "</div>";
echo "</div>\n";

输出：

<div class="item">
<div>
<img src="img/products/1.png" />
<img src="img/products/2.png" />
</div>
</div>

Answer 2

在while循环中添加一个计数器，用于为图像提供不同的ID。

   $i=1;
    while ($data = mysql_fetch_array($sql)){
     echo "<div class=\"item\">\n";
     echo "<div>";
     echo "<img id='img".$i."' src=\"img/products/".$data['photo']."\" />";
     echo "</div>";
     echo "</div>\n";
    $i++;
    }

PHP：Echo IMG标记有两个不同的ID

2 个答案: