我在从SF2.0.x迁移到SF2.7的应用程序中收到此错误:
[1] Symfony\Component\Debug\Exception\FatalErrorException: Compile Error: Cannot use isset() on the result of an expression (you can use "null !== expression" instead)
at n/a
in /var/www/html/reptooln_admin/app/cache/dev/twig/68/7f/63589dd3687cb849dd68e6b6c10aa99eda1d82f95a5f3ac52a864d200499.php line 39
我不知道什么是失败或如何解决这个问题所以我需要一些建议。这是报告Stacktrace的缓存文件中的行:
if ((((empty((isset($context["form_action"]) ? $context["form_action"] : $this->getContext($context, "form_action"))) == true) || (isnull((isset($context["form_action"]) ? $context["form_action"] : $this->getContext($context, "form_action"))) == true)) || (isset((isset($context["form_action"]) ? $context["form_action"] : $this->getContext($context, "form_action"))) == false))) {
echo " ";
$context["form_action"] = "";
echo " ";
我有这个TwigExtension:
class PDOneTwigExtension extends \Twig_Extension
{
public function getFilters()
{
return array(
'var_dump' => new \Twig_Filter_Function('var_dump'),
'empty' => new \Twig_Filter_Function('empty', array($this, 'is_empty')),
'isset' => new \Twig_Filter_Function('isset', array($this, 'is_set')),
'isnull' => new \Twig_Filter_Function('isnull', array($this, 'is_null')),
'ucfirst' => new \Twig_Filter_Function('ucfirst', array($this, 'uc_first')),
'ucwords' => new \Twig_Filter_Function('ucwords', array($this, 'uc_words')),
'count' => new \Twig_Filter_Function('count', array($this, 'co_unt')),
'sizeof' => new \Twig_Filter_Function('sizeof', array($this, 'size_of')),
'concat' => new \Twig_Filter_Function('concat', array($this, 'concat')),
'in_array' => new \Twig_Filter_Function('in_array', array($this, 'inarray')),
'array' => new \Twig_Filter_Function('array', array($this, 'array_')),
'add_to_array' => new \Twig_Filter_Function('add_to_array', array($this, 'add_to_array')),
'replace' => new \Twig_Filter_Function('replace', array($this, 'replace')),
'htmlentitydecode' => new \Twig_Filter_Function('htmlentitydecode', array($this, 'htmlentitydecode'))
);
}
public function is_empty($sentence)
{
return empty($sentence) ? true : false;
}
// rest of methods goes here
public function getName()
{
return 'pdone_twig_extension';
}
}
我在模板上使用如下:
{% if form_action|empty == true or form_action|isnull == true or form_action|isset == false %} {% set form_action = '' %} {% endif %}
这里的问题可能出在哪里?有什么建议吗?
答案 0 :(得分:20)
isset()仅适用于变量,因为传递任何其他内容都会导致解析错误。
您没有直接将变量传递给isset()
。因此,您需要先计算值,将其分配给变量,然后将其传递给isset()
。
例如,您目前正在做的事情如下:
if(isset($something === false)) { } // throws a parse error, because $something === false is not a variable
您需要做的是:
$something = false;
if(isset($something)) { ... }
答案 1 :(得分:0)
你为什么要做这么多无用的代码?
为什么不呢:
{% if form_action|empty == true %} {% set form_action = '' %} {% endif %}