我尝试使用一些计算出的度量来创建成员(我在这里称之为“MyDay”)。我在轴上返回日期成员,成员有一个我想要使用的属性。我可以返回属性本身,但不能创建成员并使用它。
WITH
MEMBER [Measures].[MyDay] as DatePart("d", MyDateDimension.CurrentMember.Properties("MyProperty"))
MEMBER MyDateDimension.[MyMember] AS
STRTOMEMBER("MyDateDimension.&[2015]&[4]&[" + CStr([Measures].[MyDay]) + "]")
MEMBER [Measures].[SomeOther] as (MyDateDimension.[MyMember], [Measures].[Other]
SELECT
{
MyDateDimension.Members)
} ON COLUMNS,
{
[Measures].[MyDay] //works,
[Measures].[SomeOther] //error
}
如果我用某个硬编码日期成员替换'MyDateDimension.CurrentMember', 它工作正常。 这也有效:
MEMBER [Measures].[SomeOther] as (STRTOMEMBER("MyDateDimension.&[2015]&[4]&[" + CStr([Measures].[MyDay]) + "]"), [Measures].[Other])
答案 0 :(得分:1)
如果你将strToMember直接放在SomeMeasure中,那么事情就会开始起作用:
WITH
MEMBER [Measures].[MyDay] AS
Datepart
("d"
,[Date].[Calendar].CurrentMember.Member_Caption
)
MEMBER [Date].[Calendar].[MyMember] AS
StrToMember
(
'[Date].[Calendar].&[200603' + Cstr([Measures].[MyDay]) + ']'
,constrained
)
MEMBER [Measures].[SomeOther] AS
(
//[Date].[Calendar].[MyMember]
StrToMember
(
'[Date].[Calendar].&[200603' + Cstr([Measures].[MyDay]) + ']'
,constrained
)
,[Measures].[Internet Sales Amount]
)
SELECT
{
[Measures].[MyDay]
,[Measures].[SomeOther]
} ON COLUMNS
,Tail
(
Descendants
(
[Date].[Calendar].[Month].&[2005]&[8]
,[Date].[Calendar].[Date]
)
,10
) ON ROWS
FROM [Adventure Works];
稍微整洁的版本:
WITH
MEMBER [Measures].[MyDay] AS
Datepart
("d"
,[Date].[Calendar].CurrentMember.Member_Caption
)
MEMBER [Measures].[MyDayString] AS
'[Date].[Calendar].&[200603' + Cstr([Measures].[MyDay]) + ']'
MEMBER [Measures].[SomeOther] AS
(
StrToMember
(
[Measures].[MyDayString]
,constrained
)
,[Measures].[Internet Sales Amount]
)
SELECT
{
[Measures].[MyDay]
,[Measures].[SomeOther]
} ON COLUMNS
,Tail
(
Descendants
(
[Date].[Calendar].[Month].&[2005]&[8]
,[Date].[Calendar].[Date]
)
,10
) ON ROWS
FROM [Adventure Works];
上面返回以下内容:
你的立方体中有这样的东西:
WITH
MEMBER [Measures].[MyDay] AS
Datepart
("d"
,MyDateDimension.CurrentMember.Properties("MyProperty")
)
MEMBER [Measures].[MyDayString] AS
StrToMember('MyDateDimension.&[2015]&[4]&[' + Cstr([Measures].[MyDay]) + ']')
MEMBER [Measures].[SomeOther] AS
(
StrToMember
(
[Measures].[MyDayString]
,constrained
)
,[Measures].[Other]
)
SELECT
{
[Measures].[MyDay]
,[Measures].[SomeOther]
} ON COLUMNS
,{MyDateDimension.MEMBERS} ON ROWS
FROM YourCube;
答案 1 :(得分:0)
尝试使用SUM
定义中的[Measures].[SomeOther]
函数。它将接受计算成员。
MEMBER [Measures].[SomeOther] as
SUM(
MyDateDimension.[MyMember],
[Measures].[Other]
)