Question

我正在尝试通过Google API返回我的Google云端硬盘中的文件列表。一切正常，但它不断返回 google.apis.drive.v2.data.file 的长列表而不是实际的文件。我的代码可能有问题，但我不确定。谢谢你的帮助！

Private Sub Button2_Click(sender As Object, e As EventArgs) Handles Button2.Click
        Dim bob As New GoogleDrive
        Dim joe As New DriveModifyDate


        Dim items As String = String.Join(Environment.NewLine, joe.GetFiles(bob.service, ""))
        MsgBox(items)

我用它来调用这段代码。

 Public Function GetFiles(ByVal service As DriveService, ByVal search As String) As IList(Of File)
        Dim Files As IList(Of File) = New List(Of File)
        Try
            'List all of the files and directories for the current user.  
            Dim list As FilesResource.ListRequest = service.Files.List
            list.MaxResults = 1000
            If (Not (search) Is Nothing) Then
                list.Q = search
            End If
            Dim filesFeed As FileList = list.Execute
            '/ Loop through until we arrive at an empty page

            While (Not (filesFeed.Items) Is Nothing)
                ' Adding each item  to the list.
                For Each item As File In filesFeed.Items
                    Files.Add(item)
                Next
                ' We will know we are on the last page when the next page token is
                ' null.
                ' If this is the case, break.
                If (filesFeed.NextPageToken Is Nothing) Then
                    Exit While
                End If
                ' Prepare the next page of results
                list.PageToken = filesFeed.NextPageToken
                ' Execute and process the next page request
                filesFeed = list.Execute

            End While
        Catch ex As Exception
            ' In the event there is an error with the request.
            MsgBox(ex.Message)
        End Try
        Return Files
    End Function

Answer 1

查看文档：{{3}}

您的函数会返回一个Google.Apis.Drive.v2.Data.File列表，如果您需要获取 OriginalFilename 属性所需的文件名，这绝对没问题。

Answer 2

service.Files.List返回一个响应主体，在该主体中的每个项目都是file resource。

要下载文件，您只需要获取downloadURL并将其作为流读取。

像这样的东西（只有我能找到的例子是C＃）

/// <summary>
  /// Download a file and return a string with its content.
  /// </summary>
  /// <param name="authenticator">
  /// Authenticator responsible for creating authorized web requests.
  /// </param>
  /// <param name="file">Drive File instance.</param>
  /// <returns>File's content if successful, null otherwise.</returns>
  public static System.IO.Stream DownloadFile(
      IAuthenticator authenticator, File file) {
    if (!String.IsNullOrEmpty(file.DownloadUrl)) {
      try {
        HttpWebRequest request = (HttpWebRequest)WebRequest.Create(
            new Uri(file.DownloadUrl));
        authenticator.ApplyAuthenticationToRequest(request);
        HttpWebResponse response = (HttpWebResponse) request.GetResponse();
        if (response.StatusCode == HttpStatusCode.OK) {
          return response.GetResponseStream();
        } else {
          Console.WriteLine(
              "An error occurred: " + response.StatusDescription);
          return null;
        }
      } catch (Exception e) {
        Console.WriteLine("An error occurred: " + e.Message);
        return null;
      }
    } else {
      // The file doesn't have any content stored on Drive.
      return null;
    }
  }

代码摘自Files:get

示例lib中的代码也是C＃抱歉。

Answer 3

要添加DalmTo和David的答案，你需要明确你的意思＆＃34; file＆＃34;。通常，Drive命名法使用＆＃34; File＆＃34;引用标题，父文件夹，dateModified等元数据。它使用术语＆＃34; media＆＃34;或＆＃34;内容＆＃34;引用文件的内容。因此，如果您希望下载内容，则需要两个阶段。首先获取你正在做的ID（尽管我建议使用fields =来限制你获取的元数据量）。然后，对于每个ID，分别使用downloadUrl下载内容，或分别为非Google和Google文件类型下载ExportLinks。如果它只是您要列出的文件名，只需显示＆＃34;标题＆＃34;属性。

使用Google Drive API获取文件列表

3 个答案: