我有一个填充了后端数据的选择框。来自我后端的数据是一个包含对象的数组:
[Object { superkund_id="4", nod_id="12068", namn="Växjö Fagrabäck"}, Object { superkund_id="5", nod_id="9548", namn="Halmstad Bågen / Pilen"}]
我使用ng-options制作选项在选择中:
<td><select class="form-control input-sm2" ng-model="selectedSupercustomer" ng-options="item.superkund_id as item.namn for item in superkundOptions" ng-change="onChangeSuperCustomer(selectedSupercustomer)" ><option value=''>Select</option></select></td>
如您所见,我使用onChangeSuperCustomer捕获所选选项:
$scope.onChangeSuperCustomer = function(selectedSupercustomer) {
//console.log(selectedSupercustomer);
}
我想要的是传递属于所选选项的整个对象,因此我可以访问属于它的所有属性。我怎么能做到这一点?
答案 0 :(得分:1)
更改ng-options以绑定整个对象item
,而不仅仅是superkund_id
:
<td><select class="form-control input-sm2" ng-model="selectedSupercustomer" ng-options="item as item.namn for item in superkundOptions" ng-change="onChangeSuperCustomer(selectedSupercustomer)" ><option value=''>Select</option></select></td>
答案 1 :(得分:0)
只需在'onChangeSuperCustomer'方法中传递'item'
即可<select class="form-control input-sm2" ng-model="selectedSupercustomer" ng-options="item.superkund_id as item.namn for item in superkundOptions"
ng-change="onChangeSuperCustomer(item)" >
<option value=''>Select</option>
</select>