我正在尝试导入Excel文件,我的逻辑是正确的:
private void SaveFileToDB(UploadedFile uploadedFile)
{
string path = Server.MapPath("uploads/" + uploadedFile.FileName);
int currentContractId = Convert.ToInt32(Session["id"]);
string connnection = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" + path + ";Extended Properties=Excel 12.0;";
OleDbConnection con = new OleDbConnection(connnection);
OleDbCommand command = new OleDbCommand();
DataTable dt = new DataTable();
OleDbDataAdapter myCommand = new OleDbDataAdapter(**"select * from [Sheet1$]"**, con);
myCommand.Fill(dt);
int count = 0;
//some code...
}
正如您所看到的,我在命令中硬编码Excel工作表的名称,我想知道如何使其动态化。
答案 0 :(得分:1)
如果您希望避免使用Interop并且只想使用oledb,则可以使用以下内容获取工作表名称:
var sheetNames = con.GetSchema("Tables");
foreach (DataRow row in sheetNames.Rows)
{
var name = row["TABLE_NAME"];
//select from this sheet
//do whatever else
}
答案 1 :(得分:0)
好吧,一种方法就是找到所有床单。
Microsoft.Office.Interop.Excel.Application xlApp = new Microsoft.Office.Interop.Excel.Application();
Microsoft.Office.Interop.Excel.Workbook excelBook = xlApp.Workbooks.Open("D:\\Book1.xlsx");
String[] excelSheets = new String[excelBook.Worksheets.Count];
int i = 0;
foreach(Microsoft.Office.Interop.Excel.Worksheet wSheet in excelBook.Worksheets)
{
excelSheets[i] = wSheet.Name;
i++;
}