我有一个小的if else语句,其中if得到输出,但不是当前的else?我试过双管,但没有运气。
我的页面顶部有一个变量 -
$portfolio_style = ( isset( $uno_theme['portfolio-style-select'] ) ? $uno_theme['portfolio-style-select'] : null );
然后我的if else不起作用 -
<?php if ( $portfolio_style == 'portfolio_style_one' || 'portfolio_style_two' ) { ?>
<div class="grid">
<?php } elseif ( $portfolio_style == 'portfolio_style_three' ) { ?>
<div class="wfull">
<?php } ?>
如果选择了一个或两个投资组合风格,我想要它,显示类'grid',否则如果选择了样式三,则显示类'wfull'
我还可以完善这段代码吗? -
$portfolio_style = ( isset( $uno_theme['portfolio-style-select'] ) ? $uno_theme['portfolio-style-select'] : null );
非常感谢
答案 0 :(得分:1)
您不能在$portfolio_style
之后省略||
变量,否则唯一的字符串'portfolio_style_two'
将始终评估为true
,如描述conversion to boolean的手册中所述:< / p>
您的代码应为:
<?php if ( $portfolio_style == 'portfolio_style_one' || $portfolio_style == 'portfolio_style_two' ) { ?>
<div class="grid">
<?php } elseif ( $portfolio_style == 'portfolio_style_three' ) { ?>
<div class="wfull">
<?php } ?>
答案 1 :(得分:0)
尝试更改if条件:
<?php if ( $portfolio_style == 'portfolio_style_one' || $portfolio_style == 'portfolio_style_two' ) { ?>
答案 2 :(得分:0)
您需要将此行更改为
if ( $portfolio_style == 'portfolio_style_one' || $portfolio_style == 'portfolio_style_two' )
答案 3 :(得分:0)
试试这个:
echo ($portfolio_style == 'portfolio_style_one' || $portfolio_style == 'portfolio_style_two') ? '<div class="grid">' : (($portfolio_style == 'portfolio_style_three' ) ? '<div class="wfull">' : '');