Question

我现在得到了这个代码，完全正常：

 <?php
  $platform_id = 7;
  $query="SELECT * FROM game WHERE game_id IN 
      (SELECT game_id FROM game_platform WHERE platform_id=".$platform_id.") 
        AND game_release BETWEEN '2015-06-00' 
         AND '2015-06-30' ORDER BY game_release";

  $result=mysqli_query($link,$query) or die (mysqli_error());
  if (mysqli_num_rows($result) > 0)
  {

  echo"<table border=1>
    <tr>
    <th width=40px>Day</th>
    <th width=270px>Title</th>
    <th width=203px>Genre</th>
    <th width=203px>Developer</th>
    <th width=205px>Publisher</th>
    <th width=61px>Retail?</th>
    <th width=30px height=30px></th>
    <th width=104px>Note</th>
    </tr>";

   while($row=mysqli_fetch_assoc($result))
   {
        list($year, $month, $day) = explode("-", $row['game_release']);
        if (checkdate($month, $day, $year)) {
              $date = (new DateTime($row['game_release']))->format("j");
        } else {
              $date = "TBC";
    }
    echo"
        <tr>
            <td> ".$date." </td>
            <td>{$row['game_name']}</td>
            <td>";
    $query="SELECT * FROM genre WHERE genre_id=".$row['game_genre']; 
    $genreresult=mysqli_query($link,$query);
        $genrerow=mysqli_fetch_assoc($genreresult);
    echo $genrerow['genre_name'];
    echo "</td>
        <td>{$row['game_dev']}</td>
            <td>{$row['game_pub']}</td>
            <td>{$row['game_type']}</td>
            <td><a href=\"{$row['game_site']}\" target=\"_blank\"><img src=\"images/officialwebsite.png\" title=\"Official website\"/></a>
            <a href=\"{$row['game_trailer']}\" target=\"_blank\"><img src=\"images/youtube.png\" title=\"Trailer\"/></a></td>
            <td>{$row['game_note']}</td>
        </tr>";
   }
   echo"</table>";
   }
   else
   {
     echo "There don't seem to be any confirmed nor rumoured releases this month!";
   }
?>

如您所见，无效日期显示为“TBC”。在我没有特定日期的数据库游戏中，例如添加为“2015-09-00”。这意味着TBC游戏列在表格的顶部，因为00在01之前。

有没有办法强制他们在有效日期的游戏下面显示？

Answer 1

更改您的查询，如下所示：

$query="SELECT * FROM game WHERE game_id IN (SELECT game_id FROM game_platform WHERE platform_id=".$platform_id.") AND game_release BETWEEN '2015-06-00' AND '2015-06-30' ORDER BY game_release like '%-00%', game_release";

强制特定查询结果到echo的底部

1 个答案: