Question

我正在尝试将缓存控制头添加到Django Rest Framework ModelViewSet。

我能弄清楚如何做的唯一方法是单独覆盖每个ViewSet操作（查看，检索，创建等）并将标题附加到该操作的响应中，如下所示。

有更好的方法吗？我可以更一般地访问所有回复，所以我不必覆盖每一个动作吗？

由于

约翰

class EntityViewSet(viewsets.ModelViewSet):
    queryset = Company.objects.all().order_by('name')

    # add cache-contol the hard way
    def list(self, request):
        response = super(EntityViewSet, self).list(request)
        response['Cache-Control'] = 'no-cache'
        return response

    def retrieve(self, request, pk=None):
        response = super(EntityViewSet, self).retrieve(request, pk=None)
        response['Cache-Control'] = 'no-cache'
        return response

    def create(self, request):
        response = super(EntityViewSet, self).create(request, data=request.data)
        response['Cache-Control'] = 'no-cache'
        return response

    router.register(r'entities', EntityViewSet)

Answer 1

根据sagarchalise的建议，我只是覆盖Django的调度方法，这有效：

class UnCachedModelViewSet(viewsets.ModelViewSet):

    def dispatch(self, *args, **kwargs):
        response = super(UnCachedModelViewSet, self).dispatch(*args, **kwargs)
        response['Cache-Control'] = 'no-cache'
        return response

class EntityViewSet(UnCachedModelViewSet):
    queryset = Company.objects.all().order_by('name')
    //no need to override each action now

是否可以在Django Rest Framework ModelViewSet中一般访问响应对象？

1 个答案: