使用我的代码,菜单会运行。但是当用户输入水果的名称(保留它)时,我希望当用户按下“V”(去查看所有水果)时说“保留”
我已经阅读了Oracle Java Collections Arraylist,根据我的理解,我要么必须使用get方法或equals方法进行编码,但我不太确定如何(我确实尝试过)
请帮忙!
import java.util.ArrayList;
import java.util.Scanner;
public class FruitApril {
public static void main(String[] args) {
TheMenu();
}
public static void TheMenu()
{
String Customer[] = new String[10];
Scanner input = new Scanner(System.in);
ArrayList<String> fruits = initFruits();
String option;
do { // loop back to here as long as Q isn't selected
System.out.println("\nMenu");
System.out.println("V: Views all fruit");
System.out.println("R: To reserve fruit");
System.out.println("Q: To exit");
option = input.next();
if (option.charAt(0) == 'V' )
{
viewAllFruit(fruits,Customer);
}
if (option.charAt(0) == 'R' )
{
reserveFruit(fruits,Customer);
}
}
while (option.charAt(0) != 'Q');
}
public static ArrayList<String> initFruits() {
ArrayList<String> theFruit = new ArrayList<String>();
theFruit.add("Plums");
theFruit.add("Grapes");
theFruit.add("Oranges");
theFruit.add("Prunes");
theFruit.add("Apples");
return theFruit;
}
public static void viewAllFruit(ArrayList<String> fruits, String
CustomerRef[])
{
for (String fruit : fruits) {
System.out.println("Fruit " + fruit + " is in stock ");
}
}
public static void reserveFruit(ArrayList<String> fruits,String
CustomerRef[])
{
Scanner input = new Scanner(System.in);
while(true) {
System.out.println("Please enter the name of the fruit you'd like
to reserve");
String Fruitn = input.next();
if (Fruitn.equals(fruits))
{
fruits.get(Fruitn);
}
}
}
答案 0 :(得分:0)
您好我已更改您的代码
import java.util.ArrayList;
import java.util.Scanner;
public class FruitApril {
public static void main(String[] args) {
TheMenu();
}
public static void TheMenu()
{
String Customer[] = new String[10];
Scanner input = new Scanner(System.in);
ArrayList<String> fruits = initFruits();
String option;
do { // loop back to here as long as Q isn't selected
System.out.println("\nMenu");
System.out.println("V: Views all fruit");
System.out.println("R: To reserve fruit");
System.out.println("Q: To exit");
option = input.next();
if (option.charAt(0) == 'V' )
{
viewAllFruit(fruits,Customer);
}
if (option.charAt(0) == 'R' )
{
reserveFruit(fruits,Customer);
}
if(option.charAt(0) == 'Q') // added this condition
{
System.exit(0);
}
}while (option.charAt(0) == 'Q');
}
public static ArrayList<String> initFruits() {
ArrayList<String> theFruit = new ArrayList<String>();
theFruit.add("Plums");
theFruit.add("Grapes");
theFruit.add("Oranges");
theFruit.add("Prunes");
theFruit.add("Apples");
return theFruit;
}
public static void viewAllFruit(ArrayList<String> fruits, String CustomerRef[])
{
for (String fruit : fruits) {
System.out.println("Fruit " + fruit + " is in stock ");
}
}
public static void reserveFruit(ArrayList<String> fruits,String CustomerRef[])
{
Scanner input = new Scanner(System.in);
while(true) {
System.out.println("Please enter the name of the fruit you'd like to reserve");
String Fruitn = input.next();
int index = fruits.indexOf(Fruitn);//added this line
if (index>=0)// added this condition
{
String fruit = fruits.get(index); //added this line
System.out.println("Reversed Fruit:"+fruit); // do according to your requirement
}
}
}
}
我已经从用户输入了表单。使用该输入我在ArrayList中找到了水果的索引然后我使用了get方法来获取该水果。你没有提到你对该字符串的反转的要求。所以我只是根据你的要求把sopComplete用于剩下的代码。
答案 1 :(得分:0)
如果ArrayList是必需的,我建议你为保留的水果创建另一个arraylist:
ArrayList<String> reservedFruits = new ArrayList<String>();
然后,一旦保留了水果,只需将水果添加到此列表中:
public static void reserveFruit(String fruitToReserve){
reservedFruits.add(fruitToReserve);
// you will want to remove the reserved fruit on your fruits Arraylist here
// so that once you view the fruits, it wont be printed as available
// i leave this method to you.
removeTheReservedFruitFromTheList(fruitToReserve);
}
然后,当客户查看您的列表(按V)时,只需系统输出两个arraylists:
// print all available fruits
for(String fruit:fruits){
System.out.println(fruit + " is available.");
}
// print all reserved fruits
for(String fruit:reservedFruits ){
System.out.println(fruit + " is reserved.");
}
我为您提供了代码段,但这应该指向正确的方向。 希望这有帮助