我需要让多个FacultyID的数组也连接到FACULTYPUBLICATION表中的同一个PubID。
问题：当选择多个教师时，只有1个教师插入到FACULTYPUBLICATIONS中。我需要找到一种方法将单个PubID连接到FACULTYPUBLICATIONS表中的多个教师
//insert form values into database
$sql = "SELECT JournalName, JournalID, Rating, JournalActive from JOURNAL where JournalActive = 1;";
//Can take out JournalActive if we do not want it
$result = mysqli_query($conn, $sql);
if (!$result) {
$message = 'Invalid query: ' . mysql_error() . "\n";
$message .= 'Whole query: ' . $query;
die($message);
echo "there was an issue";
}
$sql2 = "SELECT FName, LName, FacultyID from FACULTY where FacultyActive = 1;";
//Can take out JournalActive if we do not want it
$result2 = mysqli_query($conn, $sql2);
if (!$result2) {
$message = 'Invalid query: ' . mysql_error() . "\n";
$message .= 'Whole query: ' . $query;
die($message);
echo "there was an issue";
}
//array to hold all of the data
$journals = array();
//print out all of the first names in the database
$rownumber = 0;
while ($row = mysqli_fetch_assoc($result)) {
$journals[$rownumber][0] = $row['JournalName'];
$journals[$rownumber][1] = $row['JournalID'];
$journals[$rownumber][2] = $row['JournalRating'];
$journals[$rownumber][3] = $row['JournalActive'];
$rownumber++;
}
$faculty = array();
//print out all of the first names in the database
$rownum = 0;
while ($row = mysqli_fetch_assoc($result2)) {
$faculty[$rownum][0] = $row['FName'];
$faculty[$rownum][1] = $row['LName'];
$faculty[$rownum][2] = $row['FacultyID'];
$rownum++;
}
?>
<!DOCTYPE html>
<head>
<link href="styles.css" rel="stylesheet">
<h1> Miami University </h1>
<h4> Information Systems and Analytics Department </h4>
</head>
<body>
<div class="StyleDiv" >
<!-- coding for journal -->
<form id="form1" name="form1" method="post" action="RR2.php">
<label for="FacultyName">Faculty Name</label>
<select multiple="multiple" name="FacultyID" id="FacultyID">
<?php
for($i = 0; $i < sizeof($faculty); $i++) {
print "<option value=\"" . $faculty[$i][2] . "\">" . $faculty[$i][0] .' '. $faculty[$i][1] . "</option>\r\n";
}
?>
</select>
<br class="clear" />
<br class="clear" />
<label for="JournalID">Journal Name</label>
<select name="JournalID" id="JournalID">
<?php
for($i = 0; $i < sizeof($journals); $i++) {
print "<option value=\"" . $journals[$i][1] . "\">" . $journals[$i][0] . "</option>\r\n";
}
?>
</select>
<br class="clear" />
<label for="JournalRating">Journal Rating</label><input type="text" name="JournalRating" id="JournalRating" />
<br class="clear" />
<!-- coding for publication -->
<label for="Title">Publication Title</label><input type="text" name="PubID" id="PubID" />
<br class="clear" />
<label for="Year">Year</label><input type="text" name="Year" id="Year" />
<br class="clear" />
<label for="Volume">Volume</label><input type="text" name="Volume" id="Volume" />
<br class="clear" />
<label for="Issue">Issue</label><input type="text" name="Issue" id="Issue" />
<br class="clear" />
<label for="Comments">Comments</label><textarea name="Comments" id="Comments" cols="45" rows="5"></textarea>
<br class="clear" />
<input type="submit" name="Submit" id="Submit" value="Submit" />
<br class="clear" />
</br>
</br>
</div>
</form>
<?php
//Post Parameters
$JournalID = $_POST['JournalID'];
//for($i = 0; $i < sizeof($journals); $i++) {
//if ($JournalID = $journals[$i][1]) {
//$JournalName = $journals[$i][0];
//}
//}
$Year = $_POST['Year'];
$Comments = $_POST['Comments'];
$Volume = $_POST['Volume'];
$Issue = $_POST['Issue'];
$Title = $_POST['Title'];
$JournalRating = $_POST['JournalRating'];
$FacultyMemID = $_POST['FacultyID'];
//Query
//INSERT
$stmt = $conn->prepare(" INSERT INTO PUBLICATION ( JournalID, Year, Comments, Volume, Issue, Title, JournalRating ) VALUES ( '$JournalID', '$Year', '$Comments', '$Volume', '$Issue', '$Title', '$JournalRating' )");
$stmt->execute();
// would need to add inserts for JournalName if we re-add it in
$stmt = $conn->prepare(" INSERT INTO FACULTYPUBLICATIONS ( FacultyID, PubID ) VALUES ( '$FacultyMemID', last_insert_id() )");
$stmt->execute();
mysqli_close($conn);
?>
</body>
</html>
答案 0 :(得分：0)
要获得多个选择，请将[]添加到输入名称：
<select multiple="multiple" name="FacultyID[]" id="FacultyID">
这告诉PHP使$_POST['FacultyID']成为所有值的数组。然后你可以遍历它们：
$stmt = $conn->prepare(" INSERT INTO PUBLICATION ( JournalID, Year, Comments, Volume, Issue, Title, JournalRating ) VALUES ( ?, ?, ?, ?, ?, ?, ? )");
$stmt->bind_param('sssssss', $JournalID, $Year, $Comments, $Volume, $Issue, $Title, $JournalRating);
$stmt->execute();
$pubID = $conn->insert_id;
$stmt = $conn->prepare(" INSERT INTO FACULTYPUBLICATIONS ( FacultyID, PubID ) VALUES ( ?, ? )");
$stmt->bind_param('si', $FacultyMemID, $pubID);
for ($_POST['FacultyID'] as $FacultyMemID) {
$stmt->execute();
}
请注意，您不能在循环中使用SQL LAST_INSERT_ID()，因为在第一次迭代之后它将包含刚插入FACULTYPUBLICATIONS的行的ID，而不是在循环之前插入PUBLICATION的行。所以我使用PHP $stmt->insert_id来获取ID。
我还使用bind_param重新编码以防止SQL注入。
答案 1 :(得分：0)
这使它也可以工作，因为从原始函数调用数组。
$stmt = $conn->prepare(" INSERT INTO FACULTYPUBLICATIONS ( FacultyID, PubID ) VALUES ( ?, ? )");
$stmt->bind_param('ii', $facmemid, $pubID);
//for ($_POST['FacultyID'] as $FacultyMemID) {
for($i = 0; $i < sizeof($FacultyMemID); $i++) {
$facmemid = $FacultyMemID[$i];
$stmt->execute();
}