Question

我正在尝试创建一个分页，其中一次有5个项目，具体取决于DB中的项目数。我写了这段代码。但是我不知道如何更进一步。越野..这个更好的分页或改变

<?php

$myresult .= "<div class='pagination' >";

if ($pagenum == 1)
{
}
else
{
$pagenum = 1;
$myresult .= "<a href='javascript:newPage(\"".$pagenum."\")'>&nbsp;first&nbsp;</a>";

$myresult .= " ";

$previous = $pagenum-1;
$myresult .= "<a href='javascript:newPage(\"".$previous."\")'> &nbsp;Prev&nbsp;</a>";

if ($pagenum == $last)
{

$previous3 = $pagenum-4;
$myresult .= "<a href='javascript:newPage(\"".$previous3."\")'> &nbsp; $previous3 &nbsp;</a>";

$previous2 = $pagenum-3;
$myresult .= "<a href='javascript:newPage(\"".$previous2."\")'> &nbsp; $previous2 &nbsp;</a>";
}
if ($pagenum > 2)
{
$previous1 = $pagenum-2;
$myresult .= "<a href='javascript:newPage(\"".$previous1."\")'> &nbsp; $previous1 &nbsp;</a>";

}
if ($pagenum > 1)
{

$previous2 = $pagenum-1;
$myresult .= "<a href='javascript:newPage(\"".$previous2."\")'> &nbsp; $previous2 &nbsp;</a>";
$myresult .= " ";

}



}

$myresult .= "<span class=\"disabled\"> $pagenum </span>";



if ($pagenum == $last)
{
}
else {

if($pagenum < $last - 1)
{
$next = $pagenum+1;
$myresult .= "<a href='javascript:newPage(\"".$next."\")'>&nbsp; $next &nbsp;</a>";
}
if($pagenum < $last - 2)
{
$next1 = $pagenum+2;
$myresult .= "<a href='javascript:newPage(\"".$next1."\")'> &nbsp; $next1 &nbsp;</a>";
}
if($pagenum == 1 )
{
$next2 = $pagenum+3;
$myresult .= "<a href='javascript:newPage(\"".$next2."\")'> &nbsp; $next2 &nbsp;</a>";

$next3 = $pagenum+4;
$myresult .= "<a href='javascript:newPage(\"".$next3."\")'> &nbsp; $next3 &nbsp;</a>";
}
if($pagenum == 2 )
{
$next2 = $pagenum+3;
$myresult .= "<a href='javascript:newPage(\"".$next2."\")'> &nbsp; $next2 &nbsp;</a>";
}
$next = $pagenum+1;
$myresult .= "<a href='javascript:newPage(\"".$next."\")'>&nbsp;Next&nbsp;</a>";


$myresult .= "<a href='javascript:newPage(\"".$last."\")'>&nbsp;Last</a>";

}
$myresult .= "</div>";
$myresult .= "</br>";
?>

Answer 1

也许不是最好的答案，但这是我用过的东西：

<?php

class Pagination {

    function __construct() {

    }

    function getPaginatinationNavigation($page = 1, $num_rows, $rows_per_page, $page_name)
    {
        $lastpage = ceil($num_rows/$rows_per_page);

        $page = (int)$page;
        if ($page > $lastpage) 
        {
            $page = $lastpage;
        } 
        if ($page < 1) {
            $page = 1;
        } 

        $content='<p style="text-align: center;">';

        if ($page == 1) {
            $content.= " FIRST PREV ";
        } else {
            $content.= " <a href='$page_name?page=1'>FIRST</a> ";
            $prevpage = $page-1;
            $content.= " <a href='$page_name?page=$prevpage'>PREV</a> ";
        } 

        $content.= " ( Page $page of $lastpage ) ";

        if ($page == $lastpage) {
            $content.= " NEXT LAST ";
        } else {
            $nextpage = $page+1;
            $content.= " <a href='$page_name?page=$nextpage'>NEXT</a> ";
            $content.= " <a href='$page_name?page=$lastpage'>LAST</a> ";
        } 

        $content.= '</p>';

        return $content;

    }
}

?>

导入对象

require_once('classes/Pagination.php');

获取总行数：

$query= "SELECT COUNT(*) FROM TABLE_NAME";
$row = mysql_fetch_array($getResults);
$numRecords = $row[0];

使LIMIT根据页码限制行：

$limit = ' LIMIT ' . ($page - 1) * 25 .', 25';

查询使用限制

$query = 'SELECT * FROM TABLE_NAME' . $limit;
$getResults=mysql_query($query) or die(mysql_error());

像往常一样显示结果：

while($row = mysql_fetch_array($getResults))
{
 DISPLAY RESULTS HERE
}

使用Class吐出导航：

$pagination->getPaginatinationNavigation($page, $numRecords, 25, 'display_page_name.php');

总的来说，对于分页，您需要进行2次查询：

1）获取搜索记录的总数 2）使记录限制在范围内的那些项目：例如25到50或1000到1050

您显示来自有限查询的记录，并转到下一组记录，您将页码增加一个。

希望这会有所帮助。不要忘记从网址查询字符串中清除任何数据。

如果您希望我进一步解释，请告诉我。

使用php与mysql数据分页

1 个答案: