Question

我使用this解决方案（已接受的解决方案）不插入重复项，因为我无法设置唯一索引（表属于另一个软件），这样：

$InsertAddress = $DatabaseConnection -> prepare("INSERT INTO `tt_address` (`pid`, `tstamp`, `first_name`, `last_name`, `email`, `phone`, `address`, `city`, `zip`) SELECT * FROM (SELECT 272 AS `tmp_pid`, ? AS `tmp_tstamp`, ? AS `tmp_first_name`, ? AS `tmp_last_name`, ? AS `tmp_email`, ? AS `tmp_phone`, ? AS `tmp_address`, ? AS `tmp_city`, ? AS `tmp_zip`) AS `tmp` WHERE NOT EXISTS (SELECT `email` FROM `tt_address` WHERE `email` = ?) LIMIT 1")

$InsertAddress -> bind_param('issssssss', $Timestamp, $_POST['firstname'], $_POST['lastname'], $_POST['mail'], $_POST['phone'], $_POST['address'], $_POST['ort'], $_POST['plz'], $_POST['mail']);

$InsertAddress -> execute();

echo($DatabaseConnection -> error);

但是我收到以下错误：

列数与第1行的值计数不匹配

如果我在phpMyAdmin中复制查询并替换？使用示例数据查询有效。

有什么问题？

Answer 1

参数标记（问号）不能用于列名。

列计数仅与PHP中的值计数不匹配

1 个答案: