Question

我的if子句检查chars-variable是“字母”还是“字母”（“数字”或“数字”）并不像我想要的那样... 即使没有调用子句，它也会更改chars-variable。我已经尝试了一些东西，但似乎没有任何工作。（添加了测试打印件）

（我不想对这个程序做任何违法的事情。我只是想了解一下itertools-module。）

代码：

import itertools, sys

chars = input("Chars:" + " ")
max_length = input("Max length:" + " ")
password = input("Password:" + " ")

max_length = int(max_length)

print() #
print("Chars test:", chars) #

if chars == "letters" or "Letters":
    chars = "abcdefghijklmnopqrstuvwxyz"
    print("Chars test:", chars) #
print("Chars test:", chars) #
if chars == "numbers" or "Numbers":
    chars = "0123456789"
    print("Chars test:", chars) #
print("Chars test:", chars) #

print()

input("Press enter to start...")

print()

length = (max_length + 1) - max_length

while length <= max_length:
    results = itertools.product(chars, repeat = length)
    for result in results:
        result = "".join(result)
        if result != password:
            print("Password not found yet:", result)
        else:
            print()
            print("Password found:", result)
            print()
            input("Press enter to exit...")
            sys.exit()
    length = length + 1

print()
print("Couldn't find the password.")

# = Remove when solved.

Answer 1

if chars == "letters" or "Letters":

没有做你认为的事情。它是True，如果

chars == "letters"

或

"Letters"

由于Python中的"Letters"始终为True，因此if子句始终为True。

这样做：

if chars in ("letters", "Letters"):

和

if chars in ("numbers", "Numbers"):

If-clause：即使未调用也更改变量

1 个答案: